Answer:
The plane will be 11545.46 m far when the observer hears the sonic boom
Explanation:
Step 1: Data given
Altitude of the plane = 7800 meters
speed of sound = 311.83 m/s
Step 2:
The mach number M = vs/v
This means v/vs = 1/M
Half- angle = ∅
sin∅= v/vs
∅ = sin^-1 (v/vs)
∅ = sin^-1 (1/M)
∅ = sin^-1(1/1.48)
∅= 42.5 °
tan ∅ = h/x
⇒ with h= the altitude of the plane = 7800 meter
⇒ with x = the horizontal distance moved by the plane
x = h/tan ∅
x = 7800 / tan 42.5
x = 8512.2 meters
d = the distance between the observer and the plane when the observer hears the sonic boom is:
d = √(8512.2² + 7800²)
d = 11545.46 m
The plane will be 11545.46 m far when the observer hears the sonic boom
Answer:
The resistance is .
Explanation:
Given that,
Power = 259 kV
Current = 429 A
Resistance
We need to calculate the current in each insulator
Using formula of current
Put the value into the formula
So all 95 insulators are in parallel
We need to calculate the resistance
Using formula of resistance
Put the value into the formula
Hence, The resistance is .
Explanation:
Each resistor has a resistance of R.
In the first problem, each row of three resistors in series has a resistance or 3R.
A₂ = 4A, so the voltage drop across the rows is:
V = IR
V = (4)(3R)
V = 12R
The voltage drop equals the voltage gain (Kirchoff's voltage law). The battery has a voltage of 9V, so:
9 = 12R
R = 0.75 Ω
The three rows are in parallel with each other, so the total resistance is:
∑R = (1/(3R) + 1/(3R) + 1/(3R))⁻¹
∑R = R
∑R = 0.75 Ω
The current A₁ can be found with Ohm's law:
V = IR
9 = (A₁) (0.75)
A₁ = 12 A
Using Ohm's law to find V₁, V₂, and V₃:
V = IR
V₁ = (4)(0.75)
V₁ = 3V
V₂ = (4)(2×0.75)
V₂ = 6 V
V₃ = (4)(3×0.75)
V₃ = 9 V
In the second problem, all the resistors are in series. So the total resistance is:
∑R = 8R
The battery voltage is 16V, and A₂ = 6A. So using Ohm's law:
V = IR
16 = (6)(8R)
R = 1/3 Ω
Since there's only one loop, the current is the same at all points. So A₁ = A₂ = 6A.
Using Ohm's law to find each voltage:
V = IR
V₁ = (6)(1/3)
V₁ = 2V
V₂ = (6)(2×1/3)
V₂ = 4 V
V₃ = (6)(4×1/3)
V₃ = 8 V
V₄ = (6)(2×1/3)
V₄ = 4 V
Answer:
<em>The rebound speed of the mass 2m is v/2</em>
Explanation:
I will designate the two masses as body A and body B.
mass of body A = m
mass of body B = 2m
velocity of body A = v
velocity of body B = -v since they both move in opposite direction
final speed of mass A = 2v
final speed of body B = ?
The equation of conservation of momentum for this system is
mv - 2mv = -2mv + x
where x is the final momentum of the mass B
x = mv - 2mv + 2mv
x = mv
to get the speed, we divide the momentum by the mass of mass B
x/2m = v = mv/2m
speed of mass B = <em>v/2</em>
Answer:
The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.
Explanation: