Consider a constant density gas flowing steadily over an airfoil. Far upstream the velocity is V0. Halfway along the top surface
, the velocity has increased to 2V0. Halfway along the bottom surface, the velocity has decreased to V0/2. Find the pressure difference between the top and bottom surface at this location. State all your assumptions.
1 answer:
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Answer:
Explanation:
As we know that the displacement of the particle from the mean position is 1/5 times of its amplitude
so we have
so now we have
now we have
so the phase other particle in opposite direction is given as
so we have phase difference given as
Answer:
1. Distance travelled = 12 km.
2. Displacement = 8.6 km
Explanation:
From the question given above, the following data were obtained:
Distance 1 (d₁) = 7 km
Distance 2 (d₂) = 5 km
Total distance =?
Displacement =?
1. Determination of the distance travelled.
Distance 1 (d₁) = 7 km
Distance 2 (d₂) = 5 km
Total distance (dₜ) =?
dₜ = d₁ + d₂
dₜ = 7 + 5
dₜ = 12 km
2. Determination of the displacement.
In the attached photo, R is the displacement.
We can obtain the value of R by using the pythagoras theory as illustrated below:
R² = 7² + 5²
R² = 49 + 25
R² = 74
Take the square root of both side
R = √74
R = 8.6 km
