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madam [21]
3 years ago
13

Consider a constant density gas flowing steadily over an airfoil. Far upstream the velocity is V0. Halfway along the top surface

, the velocity has increased to 2V0. Halfway along the bottom surface, the velocity has decreased to V0/2. Find the pressure difference between the top and bottom surface at this location. State all your assumptions.

Physics
1 answer:
Mashutka [201]3 years ago
5 0

Answer:

The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.

Explanation:

You might be interested in
In the voltage multiplier experiment, why not use a zener diode?​
Svet_ta [14]

Answer:

<em>A voltage multiplier is an electrical circuit that converts AC electrical power from a lower voltage to a higher DC voltage, typically using a network of capacitors and diodes.</em>

6 0
2 years ago
3. A horizontally moving tennis ball barely clears the net, a distance y above the surface of the court. To land within the tenn
maksim [4K]

(a) The ball’s maximum speed over the net is v(max) = √2gh.

(b) The maximum speed of the horizontally moving ball clearing the net is about 27 m/s.

(c) Speed of the ball is independent of its mass.

<h3>Time of motion of the ball</h3>

The time of motion of the ball is calculated as follows;

h = vt + ¹/₂gt²

1 = 0 + ¹/₂(9.8)t²

1 = 4.9t²

t² = 1/4.9

t² = 0.204

t = 0.452 s

<h3>Horizontal speed of the ball</h3>

The horizontal speed of the ball is calculated as follows;

X = vt

v = X/t

v = (12 m)/(0.452)

v = 26.6 m/s ≈ 27 m/s  (proved)

<h3>Conservation of energy</h3>

P.E = K.E

mgh = ¹/₂mv²

gh = ¹/₂v²

2gh = v²

√2gh = v(max)

Speed of the ball is independent of its mass.

Learn more about horizontal velocity here: brainly.com/question/24681896

#SPJ1

6 0
2 years ago
You want to get a Q-taco from stripes so you head 3 miles at 45 degrees S of E. What
Cloud [144]

Trigonometry allows finding the result for the decomposition of the displacement vector is:  

           x = 2.12 mi

           y = -2.12 mi

Displacement is a vector quantity, which has modulus and direction.

The cardinal points are a reference system with respect to which measurements are made, this system is related to the Cartesian system with the East in the positive direction of the x-axis and the North with the positive direction of the y-axis.

In the attached we can see a diagram of the vector and its components, the indicated direction of 45 S of the E, in the Cartesian system where the angles are measured from the positive side of the x-axis in a counterclockwise direction is:

             θ = 360 - 45

             θ = 315º  

Let's use trigonometry to decompose the vector d = 3 mi  

              cos 315 = \frac{x}{d}  

              sin 315 =  \frac{y}{d}  

               

              x = d cos 315

              y = d sin 315

Let's calculate

              x = 3 cos 315

              y = 3 sin 315

              x = 2.12 mi

              y = -2.12 mi

The negative sign indicates that the displacement is towards the negative side, that is, towards the South.

In conclusion using trigonometry we can find the result for the decomposition of the displacement vector are:  

           x = 2.12 mi

           y = -2.12 mi

Learn more here:  brainly.com/question/1666179

3 0
3 years ago
A force on a toy airplane exerted a work of 100 J. What was the change in the kinetic energy?
klemol [59]

Answer:

it probs gos fast then it was it would be easy if u asked us if their was any mass or friton

Explanation:

7 0
3 years ago
A water discharge of 9 m3/s is to flow through this horizontal pipe, which is 0.98 m in diameter. If the head loss is given as 1
Mashutka [201]

Answer: The power required by the pump to produce a discharge of 9m³/s is 5990joules/secs.

Explanation: The given parameters from the questions are:

Flow rate Q = 9m³/s, Diameter D = 0.98m, acceleration a = 1.0, head loss(Pressure P) is given by the function 10v²/2g.

STEP 1. Find the velocity of water in the pipe from the equation:

Diameter D = (√4.Q/π.v), where v is the velocity, and Q is flow rate

Making v subject of the formula gives:

v = 4Q/π.√D =[ 4 × 9m³/s / 3.142 × (√0.98m)] = 11.69m/s.

STEP 2. Find the pressure from the relationship, P = 10v²/2g, NB. g = a

P = 10 × (11.69m/s)² / 2× 1.0m/s²

P = 683.25N/m² or Pascal.

STEP 3. Find force exerted by the pump;

Recall that Pressure P = Force/Area

But Area A = π.r², where r = D/2

Therefore, A = π.(D/2)²

A = 3.142 × [0.98m/2]² = 0.75m²

Therefore, Force = Pressure × Area

Force F = 683.25N/m² × 0.75m²

F = 512.44N.

STEP 4. Find work done

Work done W by the pump is = Force × distance d moved by the water

W = F . d

Also recall that flow rate Q = Velocity/time.

Q = v/t, we can write t = v/Q.

Time t = 11.69m/s / 9m³/s = 1.298s

Also recall that velocity v = distance d/time t, v = d/t, making d subject of formula gives v × t

Distance d = v × t = 11.69m/s × 1.298s = 15.17m.

Hence,

Work Done W = Force × distance

W = 512.44N × 15.17m = 7775.56Nm or joules.

Lastly, Power P = Work done/ time

P = 7775.56joules/1.298s

P = 5990.4joules/s.

8 0
3 years ago
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