Elastic to kinetic energy.
Bow elastic transfered to arrow kinetic energy
Answer:
11.94
Explanation:
Remark
Find the Potential Energy at the top.
Givens
m = 65 kg
h = 16.2 m
g = 9.81
PE = 65 * 9.81 * 16.2
PE = 10329.93
The tricky part is what do you do about Friction?
Formula
PE = Friction + KE
Solution
PE = 10329.93 Joules
Friction = 5700 Joules
Find the KE
10329.93 = 5700 + KE
KE = 10329.93 - 5700
KE = 4629.93
Find V from the KE formula
KE = 4629.93
m = 65
KE = 1/2 m v^2
KE = 1/2 65 v^2
4629.93 = 1/2 65 v^2
v^2 = 142.46
v = √142.46
v = 11.94
So if p=w/t
then 4400=(w)(200)
so you would multiply 4440•200 and get 880,000
The absolute refractive index is equal to the speed of light of the wave in air divided by the speed of light in the second medium. This means that it is equal to 3 x10^8 / 1.71 x10^8. This means the answer is 1.75
1. Gas
2. Hot
Are the answers.
