Answer:
Approximately . (Assuming that this table is level, and that the gravitational field strength is .
Explanation:
Convert the dimensions of this book to standard units:
.
.
Calculate the surface area of this book:
.
Pressure is the ratio between normal force and the area over which this force is applied.
.
Equivalently:
.
In this question, .
It was found that (assuming that the entire side of this book is in contact with the table.
Hence:
.
If that the table is level, this normal force would be equal to the weight of this book:
.
Assuming that the gravitational field strength is . The mass of this book would be:
.
I believe that 1 millilitre of water would have a density of 1gram/cc and that is why water is used as a basis for Specific Gravity as relative to the SG of 1 of water. For example, gold has a SG of 19.2 or it is 19.2 times heavier than water.
Answer:
Explanation:
Let assume that spring reaches its maximum compression at a height of zero. The system is modelled after the Principle of Energy Conservation and the Work-Energy Theorem:
The spring constant is cleared in the expression described above:
The Porter does no work because the force applied is perpendicular to the displacement
Explanation:
The work done by a force applied to an object is given by:
where
F is the magnitude of the force
d is the displacement
is the angle between the direction of the force and the displacement of the object
From the formula, we notice that:
- The work done is maximum when the force is parallel to the displacement (because )
- The work done is zero when the force is perpendicular to the displacement (because )
In this problem, Porter is carrying the suitcase: this means that the force he is applying is upward (to balance the weight of the suitcase, pulling down), while the displacement is in the horizontal direction: therefore, force and displacement are perpendicular, so the work done is zero.
Learn more about work:
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Answer:
The time taken by the rotating object to speed up from 15.0 s to 33.3 rad/s is 5.30 seconds.
Explanation:
It is given that,
Initial angular speed of the object,
Final angular speed of the object,
Angular acceleration of the object,
Angular acceleration of an object is object is defined as the change in angular velocity per unit time. It is given by :
t = 5.30 seconds
So, the time taken by the rotating object to speed up from 15.0 s to 33.3 rad/s is 5.30 seconds. Hence, this is the required solution.