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Keith_Richards [23]
3 years ago
7

Does anyone understand circuits?

Physics
1 answer:
Alina [70]3 years ago
5 0
Hope this helps you.

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A shopper pushes a 5.32 kg grocery cart with a 12.7 N force directed at -28.7° below horizontal. A friction force of 8.33 N push
atroni [7]

Answer:

0.8214 m/s^2

Explanation:

Fnet= Fpushed - Ffriction

Fpushed = 12.7N      Ffriction = 8.33N

Fnet = 12.7N - 8.33N = 4.37N

Fnet= mass(acceleration)

Fnet = 4.37N    mass = 5.32 kg

4.37N = 5.32 kg(acceleration)

acceleration= 0.8214 m/s^2

3 0
3 years ago
What does buoyancy depend on 
Marta_Voda [28]
... the density of the liquid
... the volume of the submerged object
8 0
4 years ago
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The velocity of a car doubles over a short period of time. Which additional information is sufficient to determine the amount of
Rom4ik [11]

Answer:

Time and velocity

Explanation:

The time taken for the velocity to double is very important to find the amount of acceleration the car acquires.

Acceleration is the rate of change of velocity with time.

  Acceleration  = \frac{v -u}{t}

v is the initial velocity

u is the final velocity

t is the time taken

 So, the velocity and time is needed to calculate the value of the acceleration the car undergoes.

4 0
3 years ago
On a journey of 600 km, a train was delayed 1 hour and 30 min after having covered 1 4 of the way. To arrive on time at the dest
mars1129 [50]

Answer:

The train travelled 10hours.

Explanation:

Using speed= distance/time ...eq1

Let the time taken by train to cover the journey be t.

Let the speed of train be s

Time= distance/speed ...eq2

Time t =600/s ...eq3

The train is delayed for 1 1/2 hours=3/2 hours

Train increased by 15km/hr.

Train travelled 1/4 of 600k.= 150km.

Speed increased by s + 15 to cover the remaining 450km

t = 150/s + 400/(s + 15) + 3/2 ..eq4

Equating eq3 and 4

600/s= 150/s + 460/(s + 15) + 3/2

450/s = 3/2 + 450/(s + 15)

3s^2 + 45s -13500=0

Solving the quadratic equation

S= -45 +-sqrt(45^2-4(3×13500)/2×3

S= 60 , -75

Hence speed of train is 60km/hr

Using eq 2 distance/speed=time

600/60=10

t= 10hours

5 0
3 years ago
The SI units for momentum are: Question 3 options: mph Newtons kg*m/s lbs*mph
Lunna [17]
The SI unit for momentum is kg*(m/s)
4 0
3 years ago
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