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Taya2010 [7]
3 years ago
10

Carbon dioxide and methane increases in the atmosphere are most associated by scientist with

Chemistry
1 answer:
Semenov [28]3 years ago
5 0
I think the answer is A, ozone depletion 
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Which of the following makes sense to round to the nearest 10?
velikii [3]

Answer:

C

Explanation:

You can’t round a phone number or Pin code

why would you round your birth year?

6 0
3 years ago
Read 2 more answers
1. How many molecules of barium hydroxide, Ba(OH)2 are there in 21.9 grams of
vladimir2022 [97]

Answer: 7.7\times 10^{22} molecules of Ba(OH)_2

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{21.9g}{171g/mol}=0.128moles

1 mole of Ba(OH)_2 contains =  6.023\times 10^{23} molecules

0.128 mole of Ba(OH)_2 contains =  \frac{6.023\times 10^{23}}{1}\times 0.128=7.71\times 10^{22} molecules

Thus there are 7.7\times 10^{22} molecules of Ba(OH)_2

3 0
3 years ago
How many moles of mg3n2 would be produced when 180.0 g of mg reacts with 85.0 g of n2?
aalyn [17]
2.47 moles are produce if 85g of N2 react with 180g of Mg
7 0
4 years ago
Will iron fillings and lead oxide powder react
Andru [333]

Answer:

Yes they woll react.

Explanation:

Ferous oxide and zinc will be product.

8 0
4 years ago
A galvanic cell is powered by the following redox reaction:2Fe+3(aq) + H2 (g) + 2OH−(aq) → 2Fe+2 (aq) + 2H2O (l)Answer the follo
ICE Princess25 [194]

Answer:

Anode: H₂(g) + 2 OH⁻(aq) → 2 H₂O(l) + 2 e⁻

Cathode: 2 Fe⁺³(aq) + 2 e⁻ → 2 Fe⁺²(aq)

E° = 1.60 V

Explanation:

Let's consider the reaction taking place in a galvanic cell.

2 Fe⁺³(aq) + H₂(g) + 2 OH⁻(aq) → 2 Fe⁺²(aq) + 2 H₂O(l)

The corresponding half-reactions are:

Anode (oxidation): H₂(g) + 2 OH⁻(aq) → 2 H₂O(l) + 2 e⁻   E°red = - 0.83 V

Cathode (reduction): 2 Fe⁺³(aq) + 2 e⁻ → 2 Fe⁺²(aq)        E°red = 0.77 V

The standard cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E° = E°red, cat - E°red, an = 0.77 V - (-0.83 V) = 1.60 V

7 0
4 years ago
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