<em>A</em><em> </em><em>time</em><em> </em><em>machine</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>device</em><em> </em><em>which </em><em>can</em><em> </em><em>transport </em><em>an</em><em> </em><em>object</em><em> </em><em>or</em><em> </em><em>person</em><em> </em><em>back</em><em> </em><em>in</em><em> </em><em>time</em><em> </em><em>or</em><em> </em><em>in</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>future</em><em>.</em><em> </em>
<em>Ali</em><em> </em><em>Razeghi</em><em> </em><em>is </em><em>the </em><em>person </em><em>who </em><em>invented</em><em> </em><em>the</em><em> </em><em>time</em><em> </em><em>machine</em><em>.</em>
Answer:
The pressure is 
Explanation:
From the question we are told that
The volume of Ne is 
The volume of CO is 
The pressure of
is
The pressure of CO is 
The number of moles of Ne present is evaluated using the ideal gas equation as

=> 
The number of moles of CO present is evaluated using the ideal gas equation as

=> 
The total number of moles of gas present is evaluated as



The total volume of gas present when valve is opened is mathematically represented as

=> 
So
From the ideal gas equation the final pressure inside the system is mathematically represented as

=> ![P_f = \frac{[\frac{4.185}{RT} ] * RT }{ 4.50}](https://tex.z-dn.net/?f=P_f%20%20%3D%20%20%5Cfrac%7B%5B%5Cfrac%7B4.185%7D%7BRT%7D%20%5D%20%20%2A%20%20RT%20%7D%7B%204.50%7D)
=> 
Answer:
H₂SO₄ will be the limiting reagent.
Explanation:
The balanced reaction is:
2 Al(OH)₃ + 3 H₂SO₄ → Al₂(SO₄)₃ + 6 H₂O
The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
To determine the limiting reagent, it is possible to use the reaction stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction).
You can use a simple rule of three as follows: if by stoichiometry 2 moles of Al(OH)₃ reacts with 3 moles of H₂SO₄, how much moles of H₂SO₄ will be needed if 0.4 moles of Al(OH)₃ react?

moles of H₂SO₄= 0.6 moles
But 0.6 moles of H₂SO₄ are not available, 0.40 moles are available. Since you have less moles than you need to react with 0.4 moles of Al(OH)₃, H₂SO₄ will be the limiting reagent.