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Molodets [167]
3 years ago
15

4. Identify What do scientists call a substance that forms during a chemical reaction?

Chemistry
1 answer:
ioda3 years ago
7 0

Answer:

4. Reactant

5. Left

I hope this helps ❤️❤️

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Substances that are readily combustible or may cause fire through friction
Dvinal [7]

Answer :

Flammable substances

Explanation :

<em>Flammable substances</em> will catch fire and continue to burn when they contact an ignition source like a spark or a flame.

For example, <em>methanol</em> is a flammable liquid.

A flammable solid may also catch fire through friction. <em>Matches</em> are flammable solids.

3 0
3 years ago
The most common source of copper (cu) is the mineral chalcopyrite (cufes2). how many kilograms of chalcopyrite must be mined to
tigry1 [53]

Answer : 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.

Solution : Given,

Mass of Cu = 300 g

Molar mass of Cu = 63.546 g/mole

Molar mass of CuFeS_2 = 183.511 g/mole

  • First we have to calculate the moles of Cu.

\text{ Moles of Cu}=\frac{\text{ Given mass of Cu}}{\text{ Molar mass of Cu}}= \frac{300g}{63.546g/mole}=4.7209moles

The moles of Cu = 4.7209 moles

From the given chemical formula, CuFeS_2 we conclude that the each mole of compound contain one mole of Cu.

So, The moles of Cu = Moles of CuFeS_2 = 4.4209 moles

  • Now we have to calculate the mass of CuFeS_2.

Mass of CuFeS_2 = Moles of CuFeS_2 × Molar mass of CuFeS_2 = 4.4209 moles × 183.511 g/mole = 866.337 g

Mass of CuFeS_2 = 866.337 g = 0.8663 Kg         (1 Kg = 1000 g)

Therefore, 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.


3 0
3 years ago
What is milliliter the same as?
Klio2033 [76]

Answer:

1 cubic centimeter

Explanation:

8 0
3 years ago
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3. The exosphere is the outer layer of the
barxatty [35]

Answer:

D. exosphere is the outer layer of the thermosphere

3 0
3 years ago
Which of these compounds are oxidizing agents?
elena55 [62]

i guess its e) Mn (VII)

if it was wrong pls let me knw


6 0
3 years ago
Read 2 more answers
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