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2 years ago

Which is a chemical property that can be used to identify calcium carbonate?

Physics

2 answers:

daser333 [38]2 years ago

8 0

Answer:

could someone at least give one answer instead of a choice between two cause that is a 50/50 chance to get it correct on a test!!

Explanation:

Anna71 [15]2 years ago

5 0

(D) reacts with acids by producing gas bubbles
Or
(A) White Color

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An igneous rock becomes buried, is subject to high heat and pressure, and recrystallizes. This rock then is eroded, transported,

nevsk [136]

Answer:

Answered

Explanation:

When an igneous rock becomes buried, is subjected to high heat and pressure, and recrystallizes it is formed into Metamorphic rock. Now this rock is eroded, transported, deposited and subsequently lithified to be converted into Sedimentary rock.

The same igneous rock is first converted into Metamorphic and then into sedimentary by the process of weathering.

5 0

3 years ago

The loaded cab of an elevator has a mass of 3.0 x 10 3 kg and moves 200 m up the shaft in 20 s at constant speed. At what averag

Alexeev081 [22]

The average rate at which the cable does work is 294,000 J/s.

The given parameters:

mass, m = 3000 kg
height, h = 200 m
time of motion, t = 20 s

The average rate at which the cable does work is calculated as follows;

$P = \frac{E}{t} \\\\P = \frac{mgh}{t} \\\\P = \frac{3000 \times 9.8 \times 200}{20} \\\\P = 294,000 \ J/s$

Thus, the average rate at which the cable does work is 294,000 J/s.

Learn more about energy and power here: brainly.com/question/13387946

4 0

2 years ago

The graph below shows the displacement of an object as a constant

SSSSS [86.1K]

Answer:help

Explanation: b.3.6 j

4 0

3 years ago

How many joules of work are done against a truck when a force of 50 N pushes it 1 kilometer away

ELEN [110]

Answer:

Work = 50,000 J

Explanation:

Work = force * distance

Given that,

force = 50N
Distance = 1km = 1000m

Work = 50 * 1000

Work = 50,000 J

8 0

2 years ago

a) What is the average useful power output of a person who does6.00×10^6Jof useful work in 8.00 h? (b) Working at this rate, how

NARA [144]

Answer:

208.33 W

141.26626 seconds

Explanation:

E = Energy = $6\times 10^6\ J$

t = Time taken = 8 h

m = Mass = 2000 kg

g = Acceleration due to gravity = 9.81 m/s²

h = Height of platform = 1.5 m

Power is obtained when we divide energy by time

$P=\frac{E}{t}\\\Rightarrow P=\frac{6\times 10^6}{8\times 60\times 60}\\\Rightarrow P=208.33\ W$

The average useful power output of the person is 208.33 W

The energy in the next part would be the potential energy

The time taken would be

$t=\frac{E}{P}\\\Rightarrow t=\frac{mgh}{208.33}\\\Rightarrow t=\frac{2000\times 9.81\times 1.5}{208.33}\\\Rightarrow t=141.26626\ s$

The time taken to lift the load is 141.26626 seconds

5 0

3 years ago