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4vir4ik [10]
2 years ago
5

A wire with a current of 1.31 A is to be formed into a circular loop of one turn. If the required value of the magnetic field at

the center of the loop is 10 µT, what is the required radius?
Physics
1 answer:
Sliva [168]2 years ago
4 0

Answer:

The required radius is 2.62 cm

Explanation:

Given;

magnitude of current in wire, I = 1.31 A

magnetic field strength, B =  10 µT

Applying Biot Savart equation;

B = \frac{\mu_o I}{2\pi r} \\\\r =  \frac{\mu_o I}{2\pi B}

where;

r is the radius of the wire

μ₀ is constant = 4π x 10⁻⁷ Tm/A

I is the current in the wire

B is the magnetic field strength

Substitute the given values and calculate the radius

r =  \frac{4 \pi *10^{-7} *1.31}{2\pi *10 *10^{-6}} = 2.62 *10^{-2} \ m = 2.62 \ cm

Therefore, the required radius is 2.62 cm

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Answer:

v(0)=2m/s

Explanation:

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Using the data provided:

\omega=\sqrt{\frac{400}{1} } =20

At the equilibrium position:

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Answer:

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Answer:

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