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4vir4ik [10]
2 years ago
5

A wire with a current of 1.31 A is to be formed into a circular loop of one turn. If the required value of the magnetic field at

the center of the loop is 10 µT, what is the required radius?
Physics
1 answer:
Sliva [168]2 years ago
4 0

Answer:

The required radius is 2.62 cm

Explanation:

Given;

magnitude of current in wire, I = 1.31 A

magnetic field strength, B =  10 µT

Applying Biot Savart equation;

B = \frac{\mu_o I}{2\pi r} \\\\r =  \frac{\mu_o I}{2\pi B}

where;

r is the radius of the wire

μ₀ is constant = 4π x 10⁻⁷ Tm/A

I is the current in the wire

B is the magnetic field strength

Substitute the given values and calculate the radius

r =  \frac{4 \pi *10^{-7} *1.31}{2\pi *10 *10^{-6}} = 2.62 *10^{-2} \ m = 2.62 \ cm

Therefore, the required radius is 2.62 cm

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if a star is 20 light minutes away and it stops creating light, how long will it be before we stop seeing the light?
Sloan [31]
20 light minutes
this is because light takes time to travel

7 0
3 years ago
You push a cart with mass 30 kg forward, giving it an acceleration of 5 m/s2How much force did you apply? O A. 0.17 N O B. 35 N
umka21 [38]

Answer:

150N

Explanation:

To find the force applied remember that force equals to Mass multiply by the Acceleration.

F=Ma

=30*5

=150N

3 0
3 years ago
A column of argon is open at one end and closed at the other. The shortest length of such a column that will resonate with a 200
ziro4ka [17]

Answer:

The speed of sound in the argon is 340 m/s.

Explanation:

Given;

fundamental frequency, f₀ = 200 Hz

length of the pipe, L = 42.5 cm = 0.425 m

A pipe that is open at one end and closed at another end is known as a closed pipe.

The wavelength for the first harmonic is calculated as;

L = Node -------> Antinode

L = λ/4

λ = 4L

The speed of the sound is calculated as;

v = fλ

where;

v is the speed of the sound

v = f x 4L

v = 200 x (4 x 0.425)

v = 340 m/s

Therefore, the speed of sound in the argon is 340 m/s.

7 0
2 years ago
Two boxes connected by a light horizontal rope are on a horizontal surface. The coefficient of kinetic fric-tion between each bo
babunello [35]

Answer:

(A). The tension in the rope that connects the boxes is 10.50 N.

(B). The value of m is 7 kg.

Explanation:

Given that,

Mass of box B = 5.00 kg

Mass of box A = m

Force = 40.0 N

Direction= 53.1°

Acceleration = 1.50 m/s²

Coefficient of kinetic friction = 0.30

(A). We need to calculate the tension in the rope that connects the boxes

Using balance equation

T=ma+m\cos\theta

Put the value into the formula

T=5\times1.50+5.00\cos53.1

T=10.50\ N

(B). We need to calculate the value of m

Using formula of tension

T=ma

m=\dfrac{T}{a}

Put the value into the formula

m=\dfrac{10.50}{1.50}

m=7\ kg

Hence, (A). The tension in the rope that connects the boxes is 10.50 N.

(B). The value of m is 7 kg.

3 0
3 years ago
A solid uniform cylinder is rolling without slipping. What fraction of its kinetic energy is rotational?
tester [92]

Answer:

Explanation:

Let m be the mass of cylinder and r be the radius. It is moving with velocity v and angular velocity is ω. Let I be the moment of inertia of the cylinder.

I = 0.5 mr²

Total kinetic energy, T = 0.5 mv² + 0.5 Iω²

T = 0.5 (mv² + 0.5 mr²ω²)

v = rω

So, T = 0.5 (mv² + 0.5 mv²) = 0.75 mv²

Rotational kinetic energy is

R = 0.5 Iω² = 0.5 x 0.5 mr²ω²

R = 0.25 mv²

So, R / T = 0.25 / 0.75 = 1/3

5 0
3 years ago
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