A wire with a current of 1.31 A is to be formed into a circular loop of one turn. If the required value of the magnetic field at
1 answer:
Answer:
The required radius is 2.62 cm
Explanation:
Given;
magnitude of current in wire, I = 1.31 A
magnetic field strength, B = 10 µT
Applying Biot Savart equation;
where;
r is the radius of the wire
μ₀ is constant = 4π x 10⁻⁷ Tm/A
I is the current in the wire
B is the magnetic field strength
Substitute the given values and calculate the radius
Therefore, the required radius is 2.62 cm
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Answer
given,
time = 10 s
ship's speed = 5 Km/h
F = m a
a is the acceleration and m is mass.
In the first case
F₁=m x a₁
where a₁ = difference in velocity / time
F₁ is constant acceleration is also a constant.
Δv₁ = 5 x 0.278
Δv₁ = 1.39 m/s
a₁ = 0.139 m/s²
F₂ =m x a₂
F₃ = F₂ + F₁
Δv₃ = 19 x 0.278
Δv₃ = 5.282 m/s
a₃=Δv₂ / t
a₃ = 0.5282 m²/s
m a₃=m a₁ + m a₂
a₃ = a₂ + a₁
0.5282 = a₂ + 0.139
a₂=0.3892 m²/s
F₂ = m x 0.3892...........(1)
F₁ = m x 0.139...............(2)
F₂/F₁
ratio =
ratio = 2.8
I attached the picture of the missing table.
Center of mass is the point such that if you apply force to it, the system would move without rotating.
We can use following formula to calculate the center of mass:
Where M is the sum of the masses of all particles.
Part 1
To calculate the x coordinate of the center of mass we will use this formula:
I will do all the calculations in the google sheet that I will share with you.
For the x coordinate of the center of mass we get:
Part 2
To calculate the y coordinate of the center of mass we will use this formula:
I will do all the calculations in the google sheet that I will share with you.
For the x coordinate of the center of mass we get:
Part 3
We will calculate speed along x and y-axis separately and then will add them together.
Total velocity is:
Once we calculate velocities we get:
Part 4
Because origin is left to our center of mass(please see the attached picture) placing fifth mass in the origin would move the center of mass to the left along the x-axis.
Part 5
If you place fifth mass in the center of the mass nothing would change. The center of mass would stay in the same place.
Here is the link to the spreadsheet:
https://docs.google.com/spreadsheets/d/1SkQHbI1BxiJnwpWbLmP0XWgcNPrGquH1K2MfN6cznVo/edit?usp=sharing
Center of mass is the point such that if you apply force to it, the system would move without rotating.
We can use following formula to calculate the center of mass:
Where M is the sum of the masses of all particles.
Part 1
To calculate the x coordinate of the center of mass we will use this formula:
I will do all the calculations in the google sheet that I will share with you.
For the x coordinate of the center of mass we get:
Part 2
To calculate the y coordinate of the center of mass we will use this formula:
I will do all the calculations in the google sheet that I will share with you.
For the x coordinate of the center of mass we get:
Part 3
We will calculate speed along x and y-axis separately and then will add them together.
Total velocity is:
Once we calculate velocities we get:
Part 4
Because origin is left to our center of mass(please see the attached picture) placing fifth mass in the origin would move the center of mass to the left along the x-axis.
Part 5
If you place fifth mass in the center of the mass nothing would change. The center of mass would stay in the same place.
Here is the link to the spreadsheet:
https://docs.google.com/spreadsheets/d/1SkQHbI1BxiJnwpWbLmP0XWgcNPrGquH1K2MfN6cznVo/edit?usp=sharing