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3 years ago

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A wire with a current of 1.31 A is to be formed into a circular loop of one turn. If the required value of the magnetic field at

the center of the loop is 10 µT, what is the required radius?

1 answer:

Sliva [168]3 years ago

4 0

Answer:

The required radius is 2.62 cm

Explanation:

Given;

magnitude of current in wire, I = 1.31 A

magnetic field strength, B = 10 µT

Applying Biot Savart equation;

$B = \frac{\mu_o I}{2\pi r} \\\\r = \frac{\mu_o I}{2\pi B}$

where;

r is the radius of the wire

μ₀ is constant = 4π x 10⁻⁷ Tm/A

I is the current in the wire

B is the magnetic field strength

Substitute the given values and calculate the radius

$r = \frac{4 \pi *10^{-7} *1.31}{2\pi *10 *10^{-6}} = 2.62 *10^{-2} \ m = 2.62 \ cm$

Therefore, the required radius is 2.62 cm

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Readme [11.4K]

1) First of all, we need to find the distance between the two charges. Their distance on the xy plane is
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2) Then, we can calculate the electrostatic force between the two charges $q_1$ and $q_2$ , which is given by
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