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lesya [120]
3 years ago
5

If Manuel exerts a force of 10 N to push a desk to the right at the same time Lynn exerts a force of 15 N to push the desk to th

e left, the desk will move to the
left
right
sideways
it won't move
Physics
1 answer:
wolverine [178]3 years ago
3 0

Answer:

The desk will move to the left.

Explanation:

Since Manuel is exerting a force of 10 N to the right, and Lynn is exerting a force of 15 N to the left, it means that Lynn is exerting a force of 5 N more than Manuel, meaning that the desk will move to the left, the direction Lynn is pushing it too.

<em>Please </em><em>like </em><em>and </em><em>mark </em><em>brainliest</em><em>!</em>

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If a runner goes 500 meters with an average speed of 7.0 m/s. How long were they running?
ivann1987 [24]

Answer: s=d/t= 500/7.0=71.42 m/s

Explanation:

5 0
3 years ago
Suppose A=BnCm, where A has dimensions LT, B has dimensions L2T-1, and C has dimensions LT2. Then the exponents n and m have the
julsineya [31]

Explanation:

The expression is :

A=B^nC^m

A =[LT], B=[L²T⁻¹], C=[LT²]

Using dimensional of A, B and C in above formula. So,

A=B^nC^m\\\\\ [LT]=[L^2T^{-1}]^n[LT^2}]^m\\\\\ [LT]=L^{2n}T^{-n}L^mT^{2m}\\\\\ [LT]=L^{2n+m}T^{2m-n}

Comparing the powers both sides,

2n+m=1 ...(1)

2m-n=1 ...(2)

Now, solving equation (1) and (2) we get :

n=\dfrac{1}{5}\\\\m=\dfrac{3}{5}

Hence, the correct option is (E).

5 0
3 years ago
A frictionless piston–cylinder device contains 7 kg of nitrogen at 100 kPa and 250 K. Nitrogen is now compressed slowly accordin
lora16 [44]

Answer: -1038.8 kJ

Explanation:

From the question, we can see that PV^n = constant. And as such, we can deduce that it is a polytropic process. Thus, we can use the polytropic work equation to calculate the needed work input.

from the question we were given

Mass of nitrogen, m = 7kg

initial temperature, T1 = 250k

Final temperature, T2 = 450k

Polytropic index, n = 1.4

Specific gas constant, R = 0.2968kJ/kgK

W = [p2 * v2 - p1 * v1] / 1 - n

W = [m * R * T2 - T1] / 1 - n

W = 7*0.2968*(450 - 250)] / 1 - 1.4

W = [7*0.2968*200] / -0.4

W = 415.52 / -0.4

W = -1038.8 kJ

5 0
3 years ago
The age of a piece of wood from an archeological site is to be determined using the Carbon-14 method. The activity of the sample
Bond [772]

Answer:

4276.98 years

Explanation:

t = age of the sample in numbers of years

T = half life of the carbon-14 isotope = 5730 yrs

λ = decay constant of carbon-14

decay constant is given as

\lambda =\frac{0.693}{T}

\lambda =\frac{0.693}{5730}

\lambda = 0.000121

A₀ = activity of Carbon-14 in living plants

A  = activity of Carbon-14 after time "t" = (0.596) A₀

Using the equation

A = A_{o} e^{-\lambda t}

(0.596) A₀  = A_{o} e^{-0.000121 t}

0.596 = e^{-0.000121 t}

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4 0
3 years ago
How far does the moon move away from earth every year?
Oxana [17]
The moon is moving away from Earth at a rate of approximately 3.78 cm per year.
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4 0
3 years ago
Read 2 more answers
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