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3 years ago

A car is traveling at a velocity of 20 m/s. the driver applies the brakes, and the car slows with an acceleration of a = -4.0 me

ters per second squared. what is the stopping difference of the car?

Physics

1 answer:

sasho [114]3 years ago

3 0

$\displaystyle\\
V = a\times t\\\\
t= \frac{V}{a} = \frac{20}{4} = 5~s\\\\
D = \frac{a\times t^2}{2} = \frac{4\times 5^2}{2} = 2 \times 25 = 50~m$

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$y = \frac{-f +/- \sqrt{f^{2} +2kmg}}{k}$

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kinetic energy change of the cylinder = ¹/₂m(v₁² - v₀²)

So ¹/₂k(y₀² - y²) - f(y - y₀) + mg(y - y₀) = ¹/₂m(v₁² - v₀²)

Since the cylinder starts at rest, v₀ = 0. Also, when it is momentarily at rest, v₁ = 0

¹/₂k(y₀² - y²) - f(y - y₀) + mg(y - y₀) = ¹/₂m(0² - 0²)

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Let y₀ = 0, then the left hand side of the equation equals zero. So,

0 = ¹/₂ky² + fy - mgy

¹/₂ky² + fy - mgy = 0

Using the quadratic formula

$y = \frac{-f +/- \sqrt{f^{2} - 4 X\frac{k}{2} X -mg}}{2 X \frac{k}{2} }\\ y = \frac{-f +/- \sqrt{f^{2} +2kmg}}{k}$

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3 years ago

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Do we know which has more potential energy? object A or B? Best answer with reasoning gets brainliest.

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Answer:

Object C has the most potential energy.

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We know the object with the most potential energy and this is the object at C.

Potential energy is the energy due to the position of a body above the ground surface.

The higher a body is above ground, the more its potential energy.

Potential energy = mass x acceleration due to gravity x height

So;

Object C has the most potential energy.

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This is because, the height and mass of the objects are not quantified using numbers.

Potential energy is a function of mass and height and acceleration due to gravity but acceleration due gravity is a constant.

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