1. The speed in kilometers per hour (Km/h) is 133.2 Km/h
2. Yes, the speed is exceeding the 125 Km/h limit
<h3>How to convert 37 m/s to Km/h</h3>
From the question given above, the following data were obtained:
- Speed (in m/s) = 37 m/s
- Speed (in Km/h) =?
We can convert 37 m/s to kilometers per hour (Km/h) by doing the following:
1 m/s = 3.6 Km/h
Therefore,
37 m/s = 37 × 3.6
37 m/s = 133.2 Km/h
Thus, 37 m/s is equivalent to 133.2 Km/h
<h3>2. How to determine if the speed is exceeding the limit</h3>
- Speed of car = 133.2 Km/h
- Speed limit = 125 Km/h
From the above, we can see that the speed of the car is greater than the speed limit.
Thus, we can conclude that the speed of the car is exceeding the speed limit.
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Distance to the moon = 4×
m.
1 m = 3.28 ft
Distance to the moon in ft = 4×
×3.28 ft
= 13.12 ×
ft
1 fathom = 6 ft
Hence, distance to the moon in fathom
=
×
≈ 2×
fathom
Answer:
See explanation
Explanation:
Nuclear energy refers to energy trapped in the nucleus of atoms. Nuclear energy holds the greatest promise for large scale electricity generation. For instance, the amount of energy released by a given mass of uranium is 2.5 million times the energy released by combustion of an equal mass of carbon.One gram of uranium produces the same energy as 1 ton of coal, 17000 cubic feet of natural gas, 5000 pounds of wood and 149 gallons of oil.
Nuclear energy does not pollute the atmosphere as fossil fuels do. However, the challenges of effective control of the nuclear reactor and disposal of radioactive waste still remain a serious concern.
However, exploitation of nuclear energy as a source of electricity remain expensive and it is not quite easy to set up a nuclear power plant. Not many countries can afford to pay for the services of experts who operate nuclear energy plants talk more of providing the required equipment.
(a) The tension on the wire when the two charges have opposite signs is 383.5 N.
(b) The tension on the wire if both charges were negative is 3.640.25 N.
The given parameters;
- <em>first charge, q₁ = 8.75 μC </em>
- <em>second charge, q₂ = -6.5 μC </em>
- <em>electric field, E = 1.85 x 10⁸ N/C</em>
- <em>distance between the two charges, r = 2.5 cm</em>
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(a)
The attractive force between the charges is calculated as follows;

The force on the negative charge due to the electric field is calculated as follows;

The tension on the wire is the resultant of the two forces and it is calculated as follows;

(b) when the two charges are negative
The repulsive force between the two charges is calculated as follows;

The force on the first negative charge due to the electric field is calculated as follows;

The force on the second negative charge due to the electric field is calculated as follows;

The tension on the wire is the resultant of the three forces and it is calculated as follows;

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