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4 years ago

(Bonus) Which of the following statements are part of The Law of Conservation of Energy?

2 answers:

7 0

Your answers would be as follows
Energy can be transmitted from one form to another, The total amount of energy will change. , Energy can be created <span>Energy cannot be destroyed</span>

Murrr4er [49]4 years ago

6 0

The answers are B, C, G, I
Hope I helped
(Don’t know if they are right)

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Our galaxy is Select one: a. one member of a large cluster of thousands of galaxies. b. one member of a small cluster of galaxie

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Answer:

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3 years ago

A student stretches out a rubber band. What primary form of energy does the stretched-out rubber band possess? A. gravitational

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Answer : )b

Explanation:

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3 years ago

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student built a simple heat engine that could lift masses. If the heat engine takes in 300 J of heat and loses 50 J to the envir

k0ka [10]

Answer:

So it will lift the mass by h = 17 m

Explanation:

As per energy conservation we know that

$Q_1 = W + Q_2$

here we know that

$Q_1 = 300 J$

$Q_2 = 50 J$

now we have

$W = 300 - 50$

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3 years ago

Which of the following bounces light in another direction?

Natali [406]

Answer:

I do believe the answer is D. prism

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3 years ago

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A mass m at the end of a spring vibrates with a frequency

Wittaler [7]

Answer:

m = 0.59 kg.

Explanation:

First, we need to find the relation between the frequency and mass on a spring.

The Hooke's law states that

$F = -kx$

And Newton's Second Law also states that

$F = ma = m\frac{d^2x}{dt^2}$

Combining two equations yields

$a = -\frac{k}{m}x$

The term that determines the proportionality between acceleration and position is defined as angular frequency, ω.

$\omega = \sqrt{\frac{k}{m}}$

And given that ω = 2πf

the relation between frequency and mass becomes

$f = \frac{1}{2\pi}\sqrt{\frac{k}{m}}$ .

Let's apply this to the variables in the question.

$0.88 = \frac{1}{2\pi}\sqrt{\frac{k}{m}}\\0.60 = \frac{1}{2\pi}\sqrt{\frac{k}{m+0.68}}\\\frac{0.88}{0.60} = \frac{\frac{1}{2\pi}\sqrt{\frac{k}{m}}}{\frac{1}{2\pi}\sqrt{\frac{k}{m+0.68}}}\\1.4667 = \frac{\sqrt{m+0.68}}{\sqrt{m}}\\2.15m = m + 0.68\\1.15m = 0.68\\m = 0.59~kg$

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3 years ago