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professor190 [17]
3 years ago
10

Which of the following bounces light in another direction?

Physics
2 answers:
Wewaii [24]3 years ago
7 0

Answer:

Explanation:

either all of the above or D <3

Natali [406]3 years ago
3 0

Answer:

I do believe the answer is D. prism

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What aspect of bouncing balls relates to matter
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Answer: An aspect of the event of various types of balls bouncing off the same floor, being matter is that all the balls consist of matter. They all occupy space and have a form of energy when moved by a force, such as a person. And for energy, like I just said, when they bounce they create energy as they bounce up and down, so if the ball were to hit some other object, it would have an impact on the still object.

The combination of the material properties of a ball (surface textures, actual materials, amount of air, hardness/ softness, and so on) affects the height of its bounce.

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Explanation:

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A particle moves in a straight line and has acceleration given by a(t) = 12t + 10. Its initial velocity is v(0) = −5 cm/s and it
soldi70 [24.7K]

Answer:

The position function is s_{t}=2t^3+5t^2-5t+9.

Explanation:

Given that,

Acceleration a =12t+10

Initial velocity v_{0} = -5\ cm/s

Initial displacement s_{0}=9\ cm

We know that,

The acceleration is the rate of change of velocity of the particle.

a = \dfrac{dv}{dt}

The velocity is the rate of change of position of the particle

v=\dfrac{dx}{dt}

We need to calculate the the position

The acceleration is

a_{t} = 12t+10

\dfrac{dv}{dt} = 12t+10

a_{t}=dv=(12t+10)dt

On integration both side

\int{dv}=\int{(12t+10)}dt

v_{t}=6t^2+10t+C

At t = 0

v_{0}=0+0+C

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Now, On integration again both side

v_{t}=\int{ds_{t}}=\int{(6t^2+10t-5)}dt

s_{t}=2t^{3}+5t^2-5t+C

At t = 0

s_{0}=0+0+0+C

C=9

s_{t}=2t^3+5t^2-5t+9

Hence, The position function is s_{t}=2t^3+5t^2-5t+9.

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