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soldier1979 [14.2K]
4 years ago
15

What is the image of the point (4,-2) after a rotation 270 degree clockwise about the origin?

Mathematics
2 answers:
vaieri [72.5K]4 years ago
4 0
The equivalent 90° CCW rotation maps (x, y) to (-y, x).
(4, -2) becomes (2, 4) after rotation.
zhannawk [14.2K]4 years ago
3 0

Answer:

The image of the point (4, -2) is (2, 4).

Step-by-step explanation:

Since, the rule of rotation 270 degree clockwise about the origin is,

(x,y)\rightarrow (-y,x)

Where, (-y,x) is the image of the point (x,y),

Thus, by the above rule,

(4,-2)\rightarrow (-(-2), 4)

Hence, the image of the point (4, -2) is (2, 4).

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The fair spinner shown is spun 2 times. The set of possible outcomes are: S = {RR, BB, YY, GG, RB, BR, RY, YR, RG, GR, BY, YB, B
kari74 [83]

Answer:

Answer is 0.375 :)

Step-by-step explanation:

3 0
4 years ago
In a large population, 3% of the people are heroin users. A new drug test correctly identifies users 93% of the time and correct
kari74 [83]

Answer:

(a) The probability tree is shown below.

(b) The probability that a person who does not use heroin in this population tests positive is 0.10.

(c) The probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d) The probability that a randomly chosen person from this population tests positive is 0.1249.

(e) The probability that a person is heroin user given that he/she was tested positive is 0.2234.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is a heroin user

<em>Y</em> = the test is correct.

Given:

P (X) = 0.03

P (Y|X) = 0.93

P (Y|X') = 0.99

(a)

The probability tree is shown below.

(b)

Compute the probability that a person who does not use heroin in this population tests positive as follows:

The event is denoted as (Y' | X').

Consider the tree diagram.

The value of P (Y' | X') is 0.10.

Thus, the probability that a person who does not use heroin in this population tests positive is 0.10.

(c)

Compute the probability that a randomly chosen person from this population is a heroin user and tests positive as follows:

P(X\cap Y)=P(Y|X)P(X)=0.93\times0.03=0.0279

Thus, the probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d)

Compute the probability that a randomly chosen person from this population tests positive as follows:

P (Positive) = P (Y|X)P(X) + P (Y'|X')P(X')

                  =(0.93\times0.03)+(0.10\times0.97)\\=0.1249

Thus, the probability that a randomly chosen person from this population tests positive is 0.1249.

(e)

Compute the probability that a person is heroin user given that he/she was tested positive as follows:

P(X|positive)=\frac{P(Y|X)P(X)}{P(positive)} =\frac{0.93\times0.03}{0.1249}= 0.2234

Thus, the probability that a person is heroin user given that he/she was tested positive is 0.2234.

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