Answer:
<em> Pressure exerted by the gas is 574.85 torr</em>
Explanation:
Atmospheric pressure = 751 torr
but 1 torr = 1 mmHg
therefore,
atmospheric pressure = 751 mmHg
1 mmHg = 133.3 Pa
therefore,
atmospheric pressure = 751 x 133.3 = 100108.3 Pa
distance labeled (tube section with mercury) = 176 mm
the pressure within the tube will be
= ρgh
where ρ is the density of mercury = 13600 kg/m^3
h is the labeled distance = 176 mm = 0.176 m
g is acceleration due to gravity = 9.81 m/s^2
= 13600 x 9.81 x 0.176 = 23481.216 Pa
The general equation for the pressure in the manometer will be
=
+
where is the atmospheric pressure
is the pressure within the tube with mercury
is the pressure of the gas
substituting, we have
100108.3 = 23481.216 +
= 100108.3 - 23481.216 = <em>76627.1 Pa</em>
This pressure can be stated in mmHg as
76627.1 /133.3 =<em> 574.85 mmHg </em>
and also equal to<em> 574.85 torr</em>