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3 years ago

Why was Becquerel’s experiment a first step in discovering radioactivity?

2 answers:

6 0

Henri Becquerel in 1896 used naturally fluorescent minerals to examine the characteristics of X-rays. He used potassium uranyl sulfate and placed it on the photographic plates covered in black paper, considering that the uranium captivated energy from the Sun and then emitted it as X-rays.

However, the hypothesis was disapproved due to overcast conditions in Paris. Due to certain reason, Becquerel decided to create his photographic plates, and it was witnessed that the images were clear and robust, claiming that the uranium discharged radiation in the absence of an external source of energy like Sun. Thus, radioactivity got discovered.

Therefore, Becquerel experiment is considered as the initial step in discovering radioactivity because it demonstrated that a substance could continuously discharge radiation even if it was not exposed to light.

galina1969 [7]3 years ago

5 0

This was because the experiment showed that a substance could emit radiation even while it was not exposed to light.

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Functional groups are most identifiable through rational chemical formulas. In organic chemistry, the most basic functional groups include hydroxyl, carboxyl, carbonyl, ester, ether, and amino functional groups.

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3 years ago

Determine the freezing point of a 3.70 m solution of phenol in benzene. Benzene has a freezing point of 5.5°C and a freezing poi

bearhunter [10]

Answer-ΔTf = Kfm

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3 years ago

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What is the gravitational force acting on an object that has a mass of 10.0 kg

Evgesh-ka [11]

GravitationL force is equal to the mass of the object multiplied by the acceleration due to gravity. Assuming that this object is on earth, the acceleration due to gravity is 9.8 m/s^2. Therefore, 10 kg multiplied by 9.8 m/s^2 is equal to 98 N for the gravitational force.

Therefore, the gravitational force acting on an object that has a mass of 10.0 kg (assuming this object is on earth) is 98 N.

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3 years ago

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Can anyone give me examples of control groups ?

alexgriva [62]

Answer:

In an experiment in which blood pressure medication is tested, one group is given the blood pressure medication while the control group is given a placebo pill.

In a test of anxiety treatment, one group attends individual therapy sessions and receives a new medication. The control group receives only an inert pill.

A treatment for drug addiction is being tested. A group of meth addicts are given the treatment while the control group is given the placebo.

Researchers are testing the effectiveness of a drug intended to reduce symptoms of Crohn's disease. Many sufferers of Crohn's disease are recruited for the effort and the group that receives the placebo is the control group.

A treatment for hair loss in men is being tested. Men of the same age range are gathered. One group receives an application with the active ingredient while the control group receives an application that appears the same but does not have the active ingredient in it.

hope this helped you

7 0

3 years ago

4.0 L of He(g), 6.0 L of N2(g), and 10. L of Ar(g), all at 0°C and 1.0 atm, are pumped into an evacuated 8.0 L rigid container,

lesantik [10]

Answer:

The final pressure in the container at 0°C is 2.49 atm

Explanation:

We apply the Ideal Gases law to know the global pressure.

We need to know, the moles of each:

P He . V He = moles of He . R . 273K

(1atm . 4L) / R . 273K = moles of He → 0.178 moles

P N₂ . V N₂ = moles of N₂ . R . 273K

(1atm . 6L) / R . 273K = moles of N₂ → 0.268 moles

P Ar . V Ar = moles of Ar . R . 273K

(1atm . 10L) / R . 273K = moles of Ar → 0.446 moles

Total moles: 0.892 moles

P . 8L = 0.892 mol . R . 273K

P = ( 0.892 . R . 273K) / 8L = 2.49 atm

R = 0.082 L.atm/mol.K

3 0

3 years ago