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3 years ago

Why was Becquerel’s experiment a first step in discovering radioactivity?

2 answers:

6 0

Henri Becquerel in 1896 used naturally fluorescent minerals to examine the characteristics of X-rays. He used potassium uranyl sulfate and placed it on the photographic plates covered in black paper, considering that the uranium captivated energy from the Sun and then emitted it as X-rays.

However, the hypothesis was disapproved due to overcast conditions in Paris. Due to certain reason, Becquerel decided to create his photographic plates, and it was witnessed that the images were clear and robust, claiming that the uranium discharged radiation in the absence of an external source of energy like Sun. Thus, radioactivity got discovered.

Therefore, Becquerel experiment is considered as the initial step in discovering radioactivity because it demonstrated that a substance could continuously discharge radiation even if it was not exposed to light.

galina1969 [7]3 years ago

5 0

This was because the experiment showed that a substance could emit radiation even while it was not exposed to light.

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What contribution did these scientists make to atomic models of the atom?

SashulF [63]

Answer:

Explanation:

Dalton's atomic theory proposed that all matter was composed of atoms, indivisible and indestructible building blocks. While all atoms of an element were identical, different elements had atoms of differing size and mass.

In 1897, J.J. Thomson discovered the electron by experimenting with a Crookes, or cathode ray, tube. He demonstrated that cathode rays were negatively charged. In addition, he also studied positively charged particles in neon gas.

Rutherford overturned Thomson's model in 1911 with his well-known gold foil experiment in which he demonstrated that the atom has a tiny and heavy nucleus. Rutherford designed an experiment to use the alpha particles emitted by a radioactive element as probes to the unseen world of atomic structure.

The Bohr model shows the atom as a small, positively charged nucleus surrounded by orbiting electrons. Bohr was the first to discover that electrons travel in separate orbits around the nucleus and that the number of electrons in the outer orbit determines the properties of an element.

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3 years ago

Which of the elements has the highest first ionization energy C Si Ge Sn Pb

Maksim231197 [3]

Carbon has the highest first ionization energy because it is the topmost atom on the periodic table

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3 years ago

Maple syrup, which comes from the sap of maple trees, is a mixture of water and natural sugars. It's a clear, brown liquid. It's

ANTONII [103]

C.) It's a Solution ..............

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3 years ago

Calculate the enthalpy for this reaction: 2C(s) + H2(g) ---> C2H2(g) ΔH° = ??? kJ Given the following thermochemical equation

nordsb [41]

Answer:

The enthalpy for given reaction is 232 kilo Joules.

Explanation:

$C_2H_2(g) + \frac{5}{2}O_2(g)\rightarrow 2CO_2(g) + H_2O(l), \Delta H^o_{1} = -1,123 kJ$ ...[1]

$C(s) + O_2(g)\rightarrow CO2(g), \Delta H^o_{2} = -340 kJ$ ..[2]

$H_2(g) + \frac{1}{2}O_2(g)\rightarrow H_2O(l) ,\Delta H^o_{3} = -211 kJ$ ..[3]

$2C(s) + H_2(g)\rightarrow C_2H_2(g),\Delta H^o_{4} =?$ ..[4]

2 × [2] + [3] - [1] ( Using Hess's law)

$\Delta H^o_{4}=2\times \Delta H^o_{2}+\Delta H^o_{3} - \Delta H^o_{1}$

$\Delta H^o_{4}=2\times (-340 kJ) + (-211 kJ) - (-1,123 kJ)$

$\Delta H^o_{4}=232 kJ$

The enthalpy for given reaction is 232 kilo Joules.

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3 years ago

26. All atoms area. positively charged, with the number of protons exceeding the number of electronsb, negatively charged, with

user100 [1]

(26) All atoms area...with the number of protons equaling the number of electrons

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(29) The nucleus of an atom is...the central core and is composed of protons and neutrons.

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3 years ago