<span>4.50, 9.00, 36.00
First, count the number of atoms of each element in a single molecule of Mg(ClO4)2.
Mg = 1 atom
Cl = 1 * 2 = 2 atoms
O = 4 * 2 = 8 atoms
Now multiply the number of atoms of each element per molecule of the compound by the number of moles of the compound. So
Mg = 1 * 4.50 = 4.50
Cl = 2 * 4.50 = 9.00
O = 8 * 4.50 = 36.00
So the answer is
4.50, 9.00, 36.00</span>
Answer:
2Ag⁺ (aq) + CrO₄⁻² (aq) ⇄ Ag₂CrO₄ (s) ↓
Ksp = [2s]² . [s] → 4s³
Explanation:
Ag₂CrO₄ → 2Ag⁺ + CrO₄⁻²
Chromate silver is a ionic salt that can be dissociated. When we have a mixture of both ions, we can produce the salt which is a precipitated.
2Ag⁺ (aq) + CrO₄⁻² (aq) ⇄ Ag₂CrO₄ (s) ↓ Ksp
That's the expression for the precipitation equilibrium.
To determine the solubility product expression, we work with the Ksp
Ag₂CrO₄ (s) ⇄ 2Ag⁺ (aq) + CrO₄⁻² (aq) Ksp
2 s s
Look the stoichiometry is 1:2, between the salt and the silver.
Ksp = [2s]² . [s] → 4s³
<span>B.)the rate of reaction</span>
