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max2010maxim [7]
2 years ago
5

The halogens, the elements of Family 17 on the periodic table, combine easily with elements from Family 1. When a halogen reacts

with a metal, what type of compound is formed?
Chemistry
1 answer:
timofeeve [1]2 years ago
4 0

Answer:

When halogen elements react with group one metals they form halide salts.

Explanation:

The elements of group 17 are called halogens. These are six elements Fluorine, Chlorine, Bromine, Iodine, Astatine. Halogens are very reactive these elements can not be found free in nature. Their chemical properties are resemble greatly with each other. As we move down the group in periodic table size of halogens increases that's way fluorine is smaller in size as compared to other halogens elements. Their boiling points also increases down the group which changes their physical states. i.e fluorine is gas while iodine is solid.

When halogen elements react with group one metals they form halide salts.

Alkali metals have one valance electron and halogens needed one electron to complete the octet thus alkali metals loses one electron which is accepted by halogens atom and form ionic compound called halide salts.

For example:

2Na + Cl₂ → 2NaCl

2K + Cl₂  → 2KCl

2Rb + Cl₂ → 2RbCl

2Li + Cl₂ → 2LiCl

With bromine:

2Na + Br₂ → 2NaBr

2K + Br₂  → 2KBr

2Rb + Br₂ → 2RbBr

2Li + Br₂ → 2LiBr

With iodine:

2Na + I₂ → 2NaI

2K +  I₂ → 2KBI

2Rb + I₂ → 2RbI

2Li + I₂ → 2LiI

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Answer:

The answer is option B.

<h3>O2-</h3>

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Compared to ultraviolet light, an electromagnetic wave that has a higher frequency will also have ________.
Nikitich [7]
  • The answer is shorter wavelength and equal speed.                        

That is, compared to ultraviolet light, an electromagnetic wave that has a higher frequency will also have shorter wavelength and equal speed.

This can be seen by the reaction given below:

 h\times \upsilon =\frac{c}{\lambda }

h= Planck's constant

c=speed of the light

 \upsilon=frquency

{\lambda }=wavelength

So, higher is the frequency, lesser is the volume while speed remains constant as c is speed of light.

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3 years ago
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A sample of nitrogen gas collected at a pressure of 1.03 atm and a temperature of 279 K is found to occupy a volume of 568 milli
DIA [1.3K]

Answer: 0.025 moles of nitrogen gas are there in the sample.

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1.03 atm

V = Volume of gas = 568 ml = 0.568 L   (1L=1000ml)

n = number of moles  = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =279K

n=\frac{PV}{RT}

n=\frac{1.03atm\times 0.568L}{0.0821L atm/K mol\times 279K}=0.025moles

0.025 moles of nitrogen gas are there in the sample.

4 0
3 years ago
A sample of hydrogen gas has an initial pressure of 2.86 atm and an initial volume of 8472 mL If the volume of the
Oliga [24]
<h3>Answer:</h3>

Gas law : Boyle's law

New pressure: 66.24 atm

<h3>Explanation:</h3>

Concept tested: Gas laws (Boyle's law)

<u>We are given,</u>

  • Initial pressure, P₁ = 2.86 atm
  • Initial volume, V₁ = 8472 mL
  • New volume, V₂ IS 365.8 mL

We need to determine the new pressure, P₂

  • According to Boyle's law , the volume of a fixed mass of a gas and the pressure are inversely proportional at constant temperature.
  • That is, P\alpha \frac{1}{V}
  • This means , PV = k (constant)
  • Therefore; P₁V₁ = P₂V₂
  • Rearranging the formula, we can get the new pressure, P₂

P₂ = P₁V₁ ÷ V₂

   = (2.86 atm × 8472 mL) ÷ 365.8 mL

   = 66.24 atm

Therefore, the new pressure is 66.24 atm

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What affect will adding sugar have on the viscosity of water?
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