Volumen of A Solid
Given a solid with a shape of a constant base B and height H, the volume is:
V = BH
The height of the solid is 1 1/4 ft. We need to calculate the area of the base.
The base consists of a larger rectangle from which has been taken a smaller rectangle.
The larger rectangle has dimensions of 9 ft by 6 ft, thus its area is:
A1 = 9 ft * 6 ft = 54 square ft
The smaller rectangle has dimensions of 2 1/2 ft by 4 ft.
The second dimension was calculated as the difference between 9 ft and 2 ft plus 3 ft. (9 ft - 3 ft - 2 ft = 4 ft).
The area of the smaller rectangle is:
A2 = 2 1/2 * 4
The mixed fraction 2 1/2 is converted to improper fraction:
2 1/2 = 2 + 1/2 = 5/2
Thus, the area is:
A2 = 5/2 * 4
A2 = 10 square feet
The area of the base is A1 - A2 = 54 square feet - 10 square feet = 44 square feet
B = 44 square feet.
Now for the volume:
V = 44 square feet * 1 1/4 feet
Again the mixed fraction is converted to a single fraction:
1 1/4 = 1 + 1/4 = 5/4
V = 44 square feet * 5/4 feet
V = 55 cubic feet
NOOOOO! Integers are whole numbers, so there are none between 0 and 1. Now, whether or not there are any numbers at all between 0 and 1 is a whole different story... :)
f(x) = 5x^2 - 4x
g(x) = 5x + 1
Therefore f - g = 5x^2 - 4x - (5x + 1)
= 5x^2 - 4x - 5x -1
= 5x^2 -9x - 1
Hope it helps :)
You answered correctly.
(a brainliest would be appreciated)
Answer:
It gains 8 cm
Step-by-step explanation:
