1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Shtirlitz [24]
3 years ago
14

When Jenny writes the pencil exerts a force of 5N on the paper 

Physics
1 answer:
Setler79 [48]3 years ago
6 0
Formula\ for\ pressure:\\\\
pressure=\frac{Force}{Area}\\\\unit\ of\ pressure[\frac{N}{m^2}=Pa]
Force=5N\\
Area=0,5mm^2=0,0000005m^2\\\\
pressure=\frac{5N}{0,0000005m^2}=10000000Pa=10MPa\\\\
Pressure\ of\ the\ pensil\ on\ the\ paper\ is\ equal\ to\ 10MPa.
You might be interested in
An isotope is a version of the same element that differs in the composition of the A) atom. B) nucleus. C) particle. Eliminate D
crimeas [40]
The correct answer is B because isotopes have different numbers of neutrons, and neutrons are located in the nucleus

Hope this helps
5 0
3 years ago
Read 2 more answers
A 0.405 kg mass is attached to a spring with a force constant of 26.3 N/m and released from rest a distance of 3.31 cm from the
miv72 [106K]

Answer:

0.231 m/s

Explanation:

m = mass attached to the spring = 0.405 kg

k = spring constant of spring = 26.3 N/m

x₀ = initial position = 3.31 cm = 0.0331 m

x = final position = (0.5) x₀ = (0.5) (0.0331) = 0.01655 m

v₀ = initial speed = 0 m/s

v = final speed = ?

Using conservation of energy

Initial kinetic energy + initial spring energy = Final kinetic energy + final spring energy

(0.5) m v₀² + (0.5) k x₀² = (0.5) m v² + (0.5) k x²

m v₀² + k x₀² = m v² + k x²

(0.405) (0)² + (26.3) (0.0331)² = (0.405) v² + (26.3) (0.01655)²

v = 0.231 m/s

8 0
4 years ago
A lad, waiting for his friend walks in the sidewalk, in front of her house, from the front door, first, he moves towards the Pos
Andreas93 [3]

His total displacement from his original position is -1 m

We know that total displacement of an object from a position x to a position x', d = final position - initial position.

d = x' - x

If we assume the lad's initial position in front of her house is x = 0 m. The lad then moves towards the positive x-axis, 5 m. He then ends up at x' = 5 m. He then finally goes back 6 m.

Since displacement = final position - initial position, and his displacement is d' = -6 m (since he moves in the negative x - direction or moves back) from his initial position of x' = 5 m.

His final position, x" after moving back 6 m is gotten from

x" - x' = -6 m

x" = -6 + x'

x" = -6 + 5

x" = -1 m

Thus, his total displacement from his original position is

d = final position - initial position

d = x" - x

d = -1 m - 0 m

d = -1 m

So, his total displacement from his original position is -1 m

Learn more about displacement here:

brainly.com/question/17587058

3 0
3 years ago
There are many interesting applications of our energy density model to the flow of blood in the human circulatory system. One in
qaws [65]

Answer:

Pressure increases due to enlargement

Explanation:

Energy density is just a fancy name for pressure

Pressure is same at the bottom of the cups (same level-Pascal's law)

thus, Air pressure 1 + h1d1g = Air pressure 2 + h2d1g

= Air pressure 3 + (h2-h1)d2g +h1d1g

from the first 2, we get that since h2>h1, AP2<AP1

from the next 2, we get that since d2<d1, AP3>AP2

from first and third, we get that AP1>AP3

thus, finally AP1>AP3>AP2

for fluids flowing in tubes (blood vessel in this case)

P+0.5dv^2 + gh is constant (also called the bernoulli equation

for the same blood vessel, the heights remain same i.e h1=h2

for same flow rate, inc in area decreases the speed at which the blood flows as vA must remain same

hence, P increases due to enlargement

5 0
3 years ago
Read 2 more answers
) A 1000 kg car travelling at 50 m/s slams into a 1500 kg parked truck in an inelastic manner as
solmaris [256]

(a)

KE = m v^2 / 2 = (1200 kg)(20 m/s)^2 / 2 = 240,000 J


(b)

The energy is entirely dissipated by the force of friction in the brake system.


(c)

W = delta KE = KEf - KEi = (0 - 240,000) J = -240,000 J



(d)

Fd = delta KE

F = (delta KE) / d = (-240,000 J) / (50 m) = -4800 N

The magnitude of the friction force is 4800 N.
8 0
4 years ago
Other questions:
  • At a certain time a particle had a speed of 87 m/s in the positive x direction, and 6.0 s later its speed was 74 m/s in the oppo
    12·1 answer
  • 1. When the fission of uranium-235 is carried out, about 0.1 percent of the mass of the reactants is lost during the reaction. W
    8·2 answers
  • What does the diagram represent?
    9·1 answer
  • What would the world be like without energy?
    15·1 answer
  • What is dark matter consisted of?
    11·2 answers
  • An object with a velocity of
    12·1 answer
  • Select the correct answer.
    8·1 answer
  • The graph below shows the position of an ant as it crawls over a flat picnic blanket. The total time for the ant to go from the
    5·1 answer
  • A biker accelerates from 22m/s to 62m/s. His acceleration was 10m/s2. How long did it take to speed up? (select the correct equa
    8·1 answer
  • How does the gravitational pull of the blue supergiants impact the direction of your star?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!