All categories

2 years ago

FO

1 answer:

N76 [4]2 years ago

8 0

The spring constant, k, will be equal to 18 N/m. The spring constant is defined as the force-to-displaced-length ratio.

<h3 /><h3>What is the spring constant?</h3>

Spring constant is defined as the ratio of force per unit displaced length.

Given data;

Mass of block,m=0.250 k

Amplitude,A = 0.125 m

Velocity,V=3.00 m/

Spring constant, K=?

The spring constant formula when the spring oscillates at the specified amplitude A:

$\rm k= \frac{v_{max}^2 m}{A} \\\\ k =\frac{3.0 m/s^2 \times 0.250 \ kg}{0.125 \ m} \\\\ k=18 \ N/m$

Hence, the spring constant, k will be 18 N/m

To learn more about the spring constant refer:

brainly.com/question/4291098

#SPJ1

You might be interested in

If a 50microAmps current is flowing then how many electrons pass a point each minute to 2 sig figs? Please add an explanation as

defon

The equation you need to use is $Q=IT$ where Q is the charge in C, I is the current in Amps and T is the time in seconds.

So we have T = 60s
I = $50 \times 10^-^6$ A
let's work out Q
$Q=IT = (50\times 10^{-6}) \times 60 = 3 \times 10^-^3$ C
this is the total charge passing a point in a minute so divide by the charge of one electron ( $1.6 \times 10^{-19}$ ) to find the number of electrons passing the point in a minute which equals $1.875 \times 10^{16}$

6 0

3 years ago

Amy uses 20N of force to push a lawn mower 10 meters. How much work does she do? *

babunello [35]

She does 200J .

We know she uses 20N of force and 10m is the distance. We multiply both numbers and we are given our answer of 200J. Hope this was helpful. :)

4 0

4 years ago

Un contenedor de 1800 N está en reposo sobre un plano inclinado a 28°, el coeficiente de fricción entre el contenedor y el plano

babunello [35]

Answer:

F = 1480.77N

Explanation:

In order to calculate the required force to push the container with a constant velocity, you take into account the the sum of force on the container is equal to zero. Furthermore, you have for an incline the following sum of forces:

$F-Wsin\alpha-F_r=0\\\\F-Wsin\alpha-N\mu cos\alpha=0\\\\F-Wsin\alpha-W\mu cos\alpha=0$ (1)

F: required force = ?

W: weight of the container = 1800N

N: normal force = weigth

α: angle of the incline = 28°

g: gravitational acceleration = 9.8m/s^2

μ: coefficient of friction = 0.4

You solve the equation (1) for F and replace the values of the other parameters:

$F=W(sin\alpha+\mu cos\alpha)\\\\F=(1800N)(sin28\°+(0.4)cos28\°)=1480.77N$

The required force to push the container for the incline with a constant velocity is 1480.77N

8 0

3 years ago

7. How many forces are acting on this object? *<br> Fnorm<br> Ffrict<br> Fapp<br> Fgray<br> Å

faust18 [17]

Answer:

Explanation:

As you can see in the free body diagram there are 4 forces acting on the body.

4 0

3 years ago

If, in general, r were calculated as r =v/i, which circuit arrangement in part a of the experiment would have the smallest error

ladessa [460]

Concept: According to Ohm's Law, the flow of electric current through a conductor is directly proportional to the potential difference across it, provided physical conditions (like temperature, pressure, volume etc.) remains same.

v = ir

or, r = v / i

Here, current (i) is measured by Ammeter which should be connected in series of any electrical circuit.

voltage (v) is measured by Voltmeter which should be connected parallel to the external resistance (r).

In the given experiment, the first arrangement of the circuit will show the smallest error because the voltmeter is connected exactly parallel to the external resistance.

In the second arrangement, the voltmeter is connected across external resistance (r) and Ammeter (A) and in this case, the voltmeter will not measure the exact potential drop across the external resistance (r). So, there would be more error.

4 0

3 years ago