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Nimfa-mama [501]
3 years ago
5

Control rods in a nuclear reactor are used to:

Physics
2 answers:
kiruha [24]3 years ago
7 0
B.absorb neutrons to prevent chain reactions which become uncontrollable
DedPeter [7]3 years ago
5 0

Control rods in a nuclear reactor are used to absorb neutrons. <em>(B)</em>

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a pumpkin with a mass of 2.5 kg was pushed toward a wall the average acceleration of the pumpkin was 10.7 miles per second squar
Sati [7]
Alright, to begin with. The unit of Force is in Newtons. Meaning the first two options are out of the answers. Now in order to find the force. You will need to take the mass and multiply that by the acceleration. Which will give you 26.75 Newtons.
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4 years ago
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Identify one harmful environmental change that occurs when a volcano erupts.
klasskru [66]
Many ecosystems and plants are damaged or destroyed when a volcano erupts.
5 0
3 years ago
The velocity of the wave involved in the Doppler effect:
Margarita [4]

The Doppler Effect provides the equation for the calculation of apparent frequency:

f=fo[vo/(vo-vr)] 

where:<span>
vo=source wave velocity 
vr=relative speed between source and observer 
f=apparent frequency 
fo=source frequency </span>

<span>
The velocity of the doppler wave is 
v=λf</span>

where λ is light wavelength. Hence,

v=λfo[vo/(vo-vr)] 

Based on the equation, we can say that wave velocity will always be defined by one and only one wavelength.

Therefore the answer is letter C.

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4 0
3 years ago
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A mass weighting 16 lbs stretches a spring 3 inches. The mass is in a medium that exerts a viscous resistance of 20 lbs when the
const2013 [10]

Answer:

The equation for the object's displacement is u(t)=0.583cos11.35t

Explanation:

Given:

m = 16 lb

δ = 3 in

The stiffness is:

k=\frac{m}{\delta } =\frac{16}{3} =5.33lb/in

The angular speed is:

w=\sqrt{\frac{k}{m} } =\sqrt{\frac{5.33*386.4}{16} } =11.35rad/s

The damping force is:

F_{D} =cu

Where

FD = 20 lb

u = 4 ft/s = 48 in/s

Replacing:

c=\frac{F_{D} }{u} =\frac{20}{48} =0.42lbs/in

The critical damping is equal:

c_{c} =\frac{2k}{w} =\frac{2*5.33}{11.35} =0.94lbs/in

Like cc>c the system is undamped

The equilibrium expression is:

u(t)=u(o)coswt+u'(o)sinwt\\u(o)=7=0.583\\u'(o)=0\\u(t)=0.583coswt\\u(t)=0.583cos11.35t

3 0
3 years ago
PLEASE HELP!
Anna [14]

Answer:

Explanation:

At constant pressure , work done by gas = P x ΔV where P is pressure and ΔV is change in volume

ΔV = 9.2 - 5.6 = 3.6 L

3.6 L = 3.6 x 10⁻³ m³

ΔV = 3.6 x 10⁻³ m³

P = 3.7 x 10³ Pa

So work done

= 3.7 x 10³ x 3.6 x 10⁻³ J

= 13.32 J .

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3 years ago
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