<span>A plane flies along a straight line path after taking off, and it ends up 210 km farther east and 90.0 km farther north, relative to where it started. we should use Pythagoras theorem for this.
distance^2= 210^2 + 90^2.=228.47km, when rounding off this would comes around 230 km</span>
The balloon was 30.65 meters above ground.
ANSWER: A
The buoyant force exerted on a 6,000-mL toy balloon by the air surrounding the balloon is 52.97N.
<h3>How to calculate buoyant force?</h3>
The buoyancy needed for an object can be calculated using the formula;
B = ρ × V × g
where;
- ρ and V are the object's density and volume respectively
- g is the acceleration due to gravity (9.81m/s²)
B = 6000 × 0.0009 × 9.81
B = 52.97N
Therefore, the buoyant force exerted on a 6,000-mL toy balloon by the air surrounding the balloon is 52.97N.
Learn more about buoyant force at: brainly.com/question/21990136
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<span>If a negatively charged rod is brought near a neutral metal sphere, no attraction would happen since the neutral sphere has no available positive charges. So, the rod won't be attracted to the sphere. Hope this answers the question. Have a nice day.</span>
Answer:
Ari catches up to Amanda at 19.3 meters
Explanation:
We have given Ari is swimming a 25-meter race.
It is given that after swimming 6 meters she catches up to Amanda in a ratio of 7:3 from the 6-meter mark.
So ,The distance between 6 meters and 25 meters = 25-6 =19 meters
It is given that she catched Amanda in ratio 7:3
So, she catched her at of the distance
So, the distance at which she catched Amanda
Ari catches 13.3 metres from 6 m marks
So the total distance = 13.33+6 =19.33 meters
So Ari catches up to Amanda at a distance of 19.33 meters