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3 years ago

Help me quick!!! please!!

Physics

2 answers:

IgorLugansk [536]3 years ago

6 0

Answer:

P=39200W

Explanation:

P=(mgh)/t

P=(40×9.8×1000)/10

P=39200W

Rudik [331]3 years ago

4 0

Answer:

39.240 W

Explanation:

Let's start by calculating the work done by the engine. We can assume that it is the same work done by the weight of the object to bring it from 40m to the surface: as much energy it takes to bring it up, the same ammount it takes to bring it down. Said work is $w= \vec F\cdot \vec{h} = mg h = 1000 \times 9.81\times 40 = 392.400 J$

At this point we can simply apply the definition of power, that is $P = \frac wt$ , to get the power of the engine is $39.240 W$

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denis-greek [22]

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Added potential energy = (weight) x (added height)

If you need to lift a 15N box 3m straight up, you have to increase its potential energy by (15 N) x (3 m) = 45 Joules .

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3 years ago

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$acceleration=\frac{\Delta\ velocity}{\Delta\ time}\\\\
v_{initial}=0,57m/s\\
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4 years ago

A mass m = 0.6 kg is released from rest at the top edge of a hemispherical bowl with radius = 1.1 meters. The mass then slides w

Aneli [31]

Answer:

The angle is $\theta = 36.24 ^o$

Explanation:

From the question we are told that

The mass is $m = 0.6 \ kg$

The radius is $r = 1.1 \ m$

The speed is $v = 3.57 \ m /s$

According to the law of energy conservation

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=> $h = \frac{1}{2 g } * v^2$

Here h is the vertical distance traveled by the mass which is also mathematically represented as

$h = r * sin (\theta )$

$\theta = sin ^{-1} [ \frac{1}{2* g* r } * v^2]$

substituting values

$\theta = sin ^{-1} [ \frac{1}{2* 9.8* 1.1 } * (3.57)^2]$

$\theta = 36.24 ^o$

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4 years ago

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ValentinkaMS [17]

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209.3kg*V = 15,320.9 kg*km/hr

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Answer:

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