Answer:
t = 5.48 × 10⁻³ s
Explanation:
Given:
ΔV = ΔVmax × sin(2πft)
frequency, f = 16.9Hz
thus,
ΔV = ΔVmax × sin(2π×16.9×ft)
Now,
Let 'R' be the resistance
Also according to the ohms law
i = V/R
where,
i = current
V = voltage
hence,
also, given at time 't' the current in the circuit is 55.0% of the peak current
thus
thus,
or
or
or
t = 5.48 × 10⁻³ s (Answer)
Answer: f = 927.55Hz
Explanation: Since the the tube is open-closed, the length of air and the wavelength of sound passing through the tube is given below
L = λ/4 where λ = wavelength.
speed of sound in air = v = 343m/s.
fundamental frequency of open closed tube = 315Hz
λ = 4L.
v = fλ
343 = 315 * 4L
343 = 1260 * L
L = 343/ 1260
L = 0.27m
In the same tube of length L = 0.27m but different medium ( helium), the speed of sound is 1010m/s.
The length of tube and wavelength are related by the formulae below
L = λ/4, λ=4L
λ = 4 * 0.27
λ = 1.087m.
v = fλ
1010 = f * 1.087
f = 1010/1.807
f = 927.55Hz
Answer:
Some types of electromagnetic waves, like radio waves, microwaves, infrared waves, visible light and ultraviolet waves, can be reflectedSome types of electromagnetic waves, like radio waves, microwaves, infrared waves, visible light and ultraviolet waves, can be reflected
Explanation:
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