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mixer [17]
3 years ago
5

Bethany has a fish tank at her house. She uses the following data table to keep track of the nitrate and phosphate levels in the

tank.
Month Nitrates Phosphates
January 8.0 mg/L 0.010 mg/L
February 8.1 mg/L 0.010 mg/L
March 7.9 mg/L 0.009 mg/L
April 9.2 mg/L 0.012 mg/L
May 9.7 mg/L 0.020 mg/L
June 9.9 mg/L 0.029 mg/L
July 10.6 mg/L 0.032 mg/L
August 10.8 mg/L 0.038 mg/L
September 11.0 mg/L 0.036 mg/L

Bethany notices that the fish tank is gradually filling with algae. Based on the data she has collected, when did the problem most likely start? Explain.
Chemistry
2 answers:
kompoz [17]3 years ago
8 0

The answer is: the problem start at April.

In April, there is increase in concentration of nitrates (from 7.9 mg/L to 9.2 mg/L) and increase in concentration of phosphates (from 0.009 mg/L to 0.012 mg/L).

If the aquarium is not properly maintained, the nitrate and the phosphate levels will continually rise and contribute to algae growth.

Water changes keep nitrates and phosphates down.

malfutka [58]3 years ago
6 0
<span>sudden increase of Nitrate and Phosphate in March to April that occurred, it causes the fish tank to produce algae</span>
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vitamins is the answer to your question

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3 years ago
A 50.0g g sample of 16n decays to 12.5g in 14.4 seconds. What is its half life
mixas84 [53]
T is amount after time t 
<span>Ao is initial amount </span>
<span>t is time </span>
<span>HL is half life </span>

<span>log (At) = log [ Ao x (1/2)^(t/HL) ] </span>
<span>log (At) = log Ao + log (1/2)^(t/HL) </span>
<span>log (At) = log Ao + (t/HL) x log (1/2) </span>

<span>( log At - log Ao) / log (1/2) = t / HL </span>
<span>log (At/Ao) / log (1/2) = t / HL </span>

<span>HL = t / [( log (At / Ao)) / log (1/2) ] </span>

<span>HL = 14.4 s / [ ( log (12.5 / 50) / log (1/2) ] </span>

<span>HL = 14.4 s / 2 = 7.2 seconds </span>
8 0
3 years ago
Please i need your help asap!
denis23 [38]

Answer:

Density is mass over volume.

Explanation:

6 0
2 years ago
How would you know if this combination is likely to be found in dirt? Please explain!
Elan Coil [88]
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4 0
2 years ago
Read 2 more answers
A helium-filled balloon has a volume of 2.48 L and a pressure of 150 kPa. The volume of the balloon increases to 2.98 L after yo
Tema [17]

Answer:

THE NEW PRESSURE OF THE HELIUM GAS AT 2.98 L VOLUME IS 124.8 kPa.

AT AN INCREASE ALTITUDE, THERE IS A LOWER PRESSURE ENVIRONMENT AND THE HELIUM GAS PRESSURE DECREASES AND HENCE AN INCREASE IN VOLUME.

Explanation:

The question above follows Boyle's law of the gas law as the temperature is kept constant.

Boyle's law states that the pressure of a fixed mass of gas is inversely proportional to the volume, provided the temperature remains constant.

Mathematically, P1 V1 = P2 V2

P1 = 150 kPa = 150 *10^3 Pa

V1 = 2.48 L

V2 = 2.98 L

P2 = ?

Rearranging the equation, we obtain;

P2 = P1 V1 / V2

P2 = 150 kPa * 2.48 / 2.98

P2 = 372 *10 ^3 / 2.98

P2 = 124.8 kPa.

The new pressure of the gas when at a height which increases the volume of the helium gas to 2.98 L is 124.8 kPa.

6 0
2 years ago
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