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mixer [17]
3 years ago
5

Bethany has a fish tank at her house. She uses the following data table to keep track of the nitrate and phosphate levels in the

tank.
Month Nitrates Phosphates
January 8.0 mg/L 0.010 mg/L
February 8.1 mg/L 0.010 mg/L
March 7.9 mg/L 0.009 mg/L
April 9.2 mg/L 0.012 mg/L
May 9.7 mg/L 0.020 mg/L
June 9.9 mg/L 0.029 mg/L
July 10.6 mg/L 0.032 mg/L
August 10.8 mg/L 0.038 mg/L
September 11.0 mg/L 0.036 mg/L

Bethany notices that the fish tank is gradually filling with algae. Based on the data she has collected, when did the problem most likely start? Explain.
Chemistry
2 answers:
kompoz [17]3 years ago
8 0

The answer is: the problem start at April.

In April, there is increase in concentration of nitrates (from 7.9 mg/L to 9.2 mg/L) and increase in concentration of phosphates (from 0.009 mg/L to 0.012 mg/L).

If the aquarium is not properly maintained, the nitrate and the phosphate levels will continually rise and contribute to algae growth.

Water changes keep nitrates and phosphates down.

malfutka [58]3 years ago
6 0
<span>sudden increase of Nitrate and Phosphate in March to April that occurred, it causes the fish tank to produce algae</span>
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Explanation:

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3 0
3 years ago
Determine the oxidation number of Cl in each of the following species.Cl2O7AlCl4-Ba(ClO2)2CIF4+
DIA [1.3K]

These are four questons and four answers:

Answers:

  • 1)  7⁺
  • 2) 1⁻
  • 3) 3⁺
  • 4) 5⁺

Explanation:

<u><em>Question 1) </em></u><u><em>Cl₂O₇:</em></u>

a) Net charge of the compound: 0

b) Rule: oxygen works with oxidation state +2, except with peroxides.

d) Rule: balance of charges: ∑ of the charges = net charge

Call X the oxidation number of Cl:

  • 2×X + 7 (-2) = 0
  • 2X - 14 = 0
  • 2X = +14
  • X = +14 /2 = + 7

<em>Conclusion: the oxidation number of Cl in Cl₂O₇ is 7⁺.</em>

<u><em>Question 2) </em></u><u><em>AlCl₄⁻</em></u>

a) Net charge of the ion: - 1

b) Rule: common oxidation number of Al in compounds: +3

c) Rule: balance of charges: ∑ charges = net charge = - 1

  • 1 (+3) + 4X = - 1
  • +3 + 4X = - 1
  • 4X = - 1 - 3
  • 4X = - 4
  • X = - 1

<em>Conclusion: the oxidation number of Cl in AlCl₄⁻ is 1 ⁻.</em>

<em><u>Question 3)</u></em><em><u> Ba(ClO₂)₂</u></em>

a) Net charge of the compound: 0

b) Rule: common oxidation number of BA in compounds: +2

c) Rule: common oxidation number of O in compounds (except in peroxides): -2

d) Rule: balance of charges: ∑ charges = net charge = 0

  • +2 + 2X + 4 (-2) = 0
  • 2X +2 - 8 = 0
  • 2X - 6 = 0
  • 2X = +6
  • X = + 3

<em>Conclusion: the oxidation number of Cl in Ba(ClO₂)₂  is 3⁺.</em>

<u><em>Question 4)</em></u><u><em> CIF₄⁺</em></u>

a) Net charge of the ion: + 1

b) Rule: common oxidation number of F : - 1 (it is the most electronegative)

c) Rule: balance of charges: ∑ charges = net charge = + 1

  • X + 4(-1) = +1
  • X - 4 = +1
  • X = +1 + 4
  • X = + 5

<em>Conclusion: the oxidation number of Cl in ClF₄⁺ is 5⁺.</em>

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3 years ago
This is true for the body being attracted as well. Bodies of water that are smaller than oceans, seas, and large lakes are _____
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Answer:

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Explanation:

4 0
3 years ago
HELP ME PLEASE URGENT:
Stolb23 [73]

Answer:

D. These elements have properties of both metals and nonmetals.

Explanation:

It can be concluded that the elements have properties of both metals and non-metals.

The elements that borders the ones described are both metals and non-metals. Most of these elements can be classified as metalloids.

On the periodic table, the elements around this region have properties of both metals and non-metals at certain temperature and pressure conditions.

3 0
3 years ago
Read 2 more answers
How many moles of hydrogen ions are formed in the ionization of 0.250 moles of H2SO4?
True [87]

Answer:

The ionization of 0.250 moles of H₂SO₄ will produce 0.5 moles of H⁺ (hydrogen ion)

Explanation:

From the ionization of H₂SO₄, we have

H₂SO₄ → 2H⁺ + SO₄²⁻

Hence, at 100% yield, one mole of H₂SO₄ produces two moles of H⁺ (hydrogen ion) and one mole of SO₄²⁻ (sulphate ion), therefore, 0.250 moles of H₂SO₄ will produce 2×0.250 moles of H⁺ (hydrogen ion) or 0.5 moles of H⁺ (hydrogen ion) and 0.25 moles of SO₄²⁻ (sulphate ion).

That is; 0.250·H₂SO₄ → 0.5·H⁺ + 0.250·SO₄²⁻.

4 0
4 years ago
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