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dusya [7]
3 years ago
14

I'd: 9872093250, password: qqqqq, join the meeting​

Chemistry
1 answer:
yanalaym [24]3 years ago
4 0
No but give me thanks
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When a solution containing 1.4000 g of Ba(NO3)2 and 2.4000 g of HSO3NH2 is boiled, a precipitate forms. One possible identity fo
Georgia [21]

Answer:

See explanation for detailed solution

Explanation:

The balanced reaction equation is Ba(NO3)2 + 2HSO3NH2 → Ba(SO3NH2)2 + 2HNO3

Number of moles of Ba(NO3)2 = 1.4 g/ 261.337 g/mol = 5.36 × 10^-3 moles

From the reaction equation;

1 mole of Ba(NO3)2 yields 1 mole of Ba(SO3NH2)2

5.36 × 10^-3 moles of Ba(NO3)2 yields 5.36 × 10^-3 moles of Ba(SO3NH2)2

For HSO3NH2

Number of moles = 2.4g/97.10 g/mol =0.0247 moles

2 moles of HSO3NH2 yields 1 mole of Ba(SO3NH2)2

0.0247 moles of HSO3NH2 yields 0.0247 ×1/2 = 0.0137 moles

Hence, Ba(NO3)2 is the limiting reactant

The theoretical yield of Ba(SO3NH2)2 is 5.36 × 10^-3 moles × 329.4986 g/mol = 1.766 g

b)

Number of moles = mass/ molar mass

Molar mass = mass/ number of moles

Molar mass = 1.6925 g/5.36 × 10^-3 moles = 315.76 g

3 0
3 years ago
each body cell of a goldfish contains 94 chromosomes.how many chromosomes are contained in a goldfish sex cell?
Shalnov [3]
47 I believe not 100% sure
8 0
3 years ago
If a person had the values for an objects density and volume, what value can be calculated
zavuch27 [327]

Hello there! With the values of density and volume, you would be able to find the object's mass.

Density is found by dividing the mass by the volume, so you could place in the values of the density and the volume to get the mass.

For example:

500 = mass/10

The 500 being density and 100 being volume. You would use simple math rules and multiply 10 by 500, and you'd get 5000, therefore using the density and volume values and giving you the mass.

I hope I could help you and have a great day!

5 0
3 years ago
Read 2 more answers
Use the Lab Report document as a template. Use the descriptions and examples of each part to help you write your Lab Report. You
GarryVolchara [31]
This link might help you!!

https://www.eiu.edu/biology/bio1500/writing_a_lab_report.pdf
6 0
2 years ago
If 4000 g of Fe2O3 reacts, how many moles of CO are needed?<br> (add work)
7nadin3 [17]

Answer:

75.15 mol.

Explanation:

  • Firstly, we need to write the balanced equation of the reaction:

<em>Fe₂O₃ + 3CO → 2Fe + 3CO₂.</em>

It is clear that 1.0 mole of Fe₂O₃ reacts with 3.0 moles of CO to produce 2.0 moles of Fe and 3.0 moles of CO₂.

∴ Fe₂O₃ reacts with CO with (1: 3) molar ratio.

  • we need to calculate the no. of moles of (4000 g) of Fe₂O₃:

<em>no. of moles of Fe₂O₃ = mass/molar mass</em> = (4000 g)/(159.69 g/mol) = <em>25.05 mol.</em>

<u>Using cross multiplication:</u>

1.0 mole of Fe₂O₃ needs → 3.0 moles of CO,

∴ 25.05 mole of Fe₂O₃ needs → ??? moles of CO.

<em>∴ The no. of moles of CO needed</em> = (3.0 mol)(25.05 mol)/(1.0 mol) =<em> 75.15 mol.</em>

5 0
4 years ago
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