A Storage shed has the shape of an upside down cone. The shed has a volume of 209 cubic meters and is 10 meters wide. To the nea
1 answer:
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Answer:
A. 60 degrees
Step-by-step explanation:
Solution to sin(x/2)=(/2)
By looking at this equation, I can identify that the answer must be within the first quadrant since the numerator and denominator are both positive.
Since it is in the first quadrant, the range of the value of the answer must be between 0 degrees less than or equal to x less than or equal to 90 degrees.
I can also identify that this is a 30, 60, 90 degree triangle because it has a and 2 as the numerator and denominator; in this case this tells us that we are dealing with a 30, 60, 90 degree triangle because that is the only triangle with those 2 respective sides.
Once identifying those two pieces of information, we can then determine the answer.
Since sin is equal Opposite/Hypotenuse, we can then substitute the sides of the triangle (, 2) to find the angle (unknown).
So the equation would look like this,
Sinx/2=/2 (
representing the opposite side of the angle; 2 representing the Hypotenuse of the triangle)
We can then conclude that 60 degrees is the unknown angle, due to the nature of a 30 60 90 degree triangle.
*Use the attachment for reference
Therefore, the answer, 60 degrees, is a solution to the equation "sin(x/2)=(/2)"
Distribute
Combine like terms
Add 1 and subtract 6x from each side
0 = 12
The equation has no real solution
Answer with Step-by-step explanation:
Since we have given that
Initial velocity = 50 ft/sec =
Initial height of ball = 5 feet =
a. What type of function models the height (ℎ, in feet) of the ball after tt seconds?
As we know the function for height h with respect to time 't'.
b. Explain what is happening to the height of the ball as it travels over a period of time (in tt seconds).
What function models the height, ℎ (in feet), of the ball over a period of time (in tt seconds)?
if it travels over a period of time then time becomes continuous interval . so it will use integration over a period of time
Our function becomes,