The time interval with respect to Ed is 4.88 ×10³ s.
A frame of reference is a set of reference points—geometric points whose positions are known mathematically and physically—that define the origin, orientation, and scale of an abstract coordinate system.
If a body does not continuously adjust its position in relation to its environment throughout the course of time, it is said to be at rest.
In the frame S', Dina and Owen are at rest.
The speed of the ball with respect to Owen, u =0.800c
The speed of the frame S' with respect to frame S, v = 0.600c
Distance between Dina and Owen, L(p) = 1.8 × 10¹² m
Speed of light, c = 3 × 10⁸ m/s
Now, for time interval using the Lorentz transformation equation:
Δt = 1 / [ √( 1 - (v²/c²)] ( Δt' + (vΔx'/c²))
Now, v = 0.6c as S' is moving with respect to frame S.
Hence, the time take is:
Δt = 1 / [ √( 1 - ((0.6c)²/c²)] ( 7.5 ×10³ + [(-0.6c)(1.8 × 10¹²)/c²))
Δt = 1.25( 75000 - 3600)
Δt = 4.88 ×10³ s
The total time taken by the ball with respect to Ed is 4.88 ×10³ s.
Learn more about the frame of reference here:
brainly.com/question/10962551
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