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SashulF [63]
3 years ago
9

How does energy from the sun affect the motion of molecules in a solid compared to molecules in a gas

Physics
1 answer:
cricket20 [7]3 years ago
6 0
The speed would vary depending on where the molecules are found. Molecules in<span> gas will move faster than they would in liquid.Hope this helps!!</span>
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The total energy in a substance as a result of the motion and position of all the particles is _________. a. heat b. temperature
bonufazy [111]
The answer would be Thermal Energy.
3 0
3 years ago
A child sits on a merry-go-round, 1.5 meters from the center. The merry-go-round is turning at a constant rate, and the child is
exis [7]

Answer:

5 .07 s .

Explanation:

The child will move on a circle of radius r

r = 1.5 m

Let the velocity of rotation = v

radial acceleration = v² / r

v² / r = 2.3

v² = 2.3 r = 2.3 x 1.5

= 3.45

v = 1.857 m /s

Time of revolution = 2π r / v

= 2 x 3.14 x 1.5 / 1.857

= 5 .07 s .

5 0
3 years ago
If an object is moving, then the magnitude of its ____ cannot be zero.
Bad White [126]
If an object is moving, then its speed and the magnitude
of its velocity aren't zero. 

If its velocity is constant (speed doesn't change and it's
moving in a straight line), then its acceleration is zero.

Looks like choice-D sums it up nicely.
7 0
3 years ago
2) A traffic light of weight 100 N is supported by two ropes as shown. Let T1 and T2 are the tensions.
GarryVolchara [31]

Hi there!

a.

We know that:

\Sigma F_y = 0 \\\\\Sigma F_x = 0

Begin by determining the forces in the vertical direction:

W = weight of traffic light

T₁sinθ = vertical component of T₁

T₂sinθ = vertical component of T₂

b.

The ropes provide a horizontal force:

T₁cosθ = Horizontal component of T1

T₂cosθ = Horizontal component of T2

Thus:

0 = T₁cosθ  - T₂cosθ

T₁cosθ = T₂cosθ

T₁ = T₂

c.

Since the angles for both ropes are the same, we can say that:

T₁ = T₂

Sum the forces:

ΣFy = T₁sinθ + T₁sinθ - W = 0

2T₁sinθ = W

d.

Now, we can begin by solving for the tensions:

2T₁sinθ = W

T_1 = T_2 =  \frac{W}{2sin\theta} = \frac{100}{2sin(37)} = \boxed{83.08 N}

8 0
3 years ago
A 1.0 kg copper rod rests on two horizontal rails 1.0 m apart and carries a current of 50 A from one rail to the other.
vagabundo [1.1K]

Answer

given,

mass of copper rod = 1 kg

horizontal rails = 1 m

Current (I) = 50 A

coefficient of static friction = 0.6

magnetic force acting on a current carrying wire is

           F = B i L

Rod is not necessarily vertical

F_x =i L B_d

F_y= i L B_w

the normal reaction N = mg-F y

static friction       f = μ_s (mg-F y )

horizontal acceleration is zero

F_x-f = 0

iLBd = \mu_s(mg-F_y )

 B_w = B sinθ

 B_d = B cosθ

iLB cosθ= μ_s (mg- iLB sinθ)

B = \dfrac{\mu_smg}{i(cos\theta +\mu_s sin\theta)}

\theta =tan{-1}{\mu_s}

\theta =tan{-1}{0.6}

\theta = 31^0

B = \dfrac{0.6\times 1 \times 9.8}{50(cos31^0 +0.6 sin31^0)}

       B = 0.1 T

4 0
3 years ago
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