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viktelen [127]
2 years ago
9

Two objects that may be considered point masses are initially separated by a distance d. The separation distance is then decreas

ed to d/4. How does the gravitational force between these two objects change as a result of the decrease?
Physics
1 answer:
ozzi2 years ago
8 0

Answer:

Increased by 16 times

Explanation:

F = Gravitational force between two bodies

G = Gravitational constant = 6.67408 × 10⁻¹¹ m³/kg s²

m₁ = Mass of one body

m₂ = Mass of other body

d = distance between the two bodies

F=\frac{Gm_1m_2}{d^2}\\ F=\frac{1}{d^2}\quad \text {(as G and masses are constant)}

F_{new}=\frac{1}{\left (\frac{d}{4}\right )^2}\\\Rightarrow F_{new}=\frac{1}{\frac{d^2}{16}}\\\Rightarrow F_{new}={16}\times \frac{1}{d^2}\\\Rightarrow F_{new}=16\times F

∴Force will increase 16 times

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A 15-ft3 tank contains oxygen initially at 14.7 psia and 80°F. A paddle wheel within the tank is rotated until the pressure insi
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Explanation:

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        \Delta U = W_{in} - Q_{out}

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Therefore, we will calculate the final temperature as follows.

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Now, we will calculate the mass as follows.

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        W_{in} = Q_{out} + mC_{v} (T_{2} - T_{1})

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            W_{in} = Q_{out} + mC_{v} (T_{2} - T_{1})

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Answer:

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Explanation:

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