Can someone help quick

I WILL MAKE YOU BRAINLIEST ! :Which factor varies between the isotopes of an element?

FrozenT [24]

C. The neutron number.

An element is determined based on how many protons has, if the protons number change then you got a new element.

If the number of neuron change you got the same element except it will be a bit heavier or lighter if you are gaining or loosing neutrons. Those variations of an element are called the isotops of the element.

The protons and neutrons toghether form the nucleus of the atom that is heavy and dense as an elephant.

The electrons are light as fleas and stay on the shels of around the nucleus and if they are more then the number of protons they make the atom negatively charged and vice versa.

7 0

2 years ago

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Which of the following is a property of both solids and liquids?

givi [52]

I would say none because thats the only one that makes any sence.

7 0

3 years ago

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A 15.0 g sample of nickel metal is heated to 100.0 degrees C and dropped into 55.0 g of water, initially at 23.0 degrees C. Assu

OLEGan [10]

Answer: The final temperature of nickel and water is $25.2^{o}C$ .

Explanation:

The given data is as follows.

Mass of water, m = 55.0 g,

Initial temp, $(t_{i}) = 23^{o}C$ ,

Final temp, $(t_{f})$ = ?,

Specific heat of water = 4.184 $J/g^{o}C$ ,

Now, we will calculate the heat energy as follows.

q = $mS \Delta t$

= $55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)$

Also,

mass of Ni, m = 15.0 g,

Initial temperature, $t_{i} = 100^{o}C$ ,

Final temperature, $t_{f}$ = ?

Specific heat of nickel = 0.444 $J/g^{o}C$

Hence, we will calculate the heat energy as follows.

q = $mS \Delta t$

= $15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)$

Therefore, heat energy lost by the alloy is equal to the heat energy gained by the water.

$q_{water}(gain) = -q_{alloy}(lost)$

$55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)$ = -( $15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)$ )

$t_{f} = \frac{25.9^{o}C}{1.029}$

= $25.2^{o}C$

Thus, we can conclude that the final temperature of nickel and water is $25.2^{o}C$ .

6 0

3 years ago

An aqueous sodium acetate, NaC2H3O2 , solution is made by dissolving 0.395 mol NaC2H3O2 in 0.505 kg of water. Calculate the mola

liq [111]

<u>Answer:</u> The molality of $NaC_2H_3O_2$ solution is 0.782 m

<u>Explanation:</u>

Molality is defined as the amount of solute expressed in the number of moles present per kilogram of solvent. The units of molarity are mol/kg. The formula used to calculate molality:

$\text{Molality of solution}=\frac{\text{Moles of solute}}{\text{Mass of solvent (in kg)}}$ .....(1)

Given values:

Moles of $NaC_2H_3O_2$ = 0.395 mol

Mass of solvent (water) = 0.505 kg

Putting values in equation 1, we get:

$\text{Molality of }NaC_2H_3O_2=\frac{0.395mol}{0.505kg}\\\\\text{Molality of }NaC_2H_3O_2=0.782m$

Hence, the molality of $NaC_2H_3O_2$ solution is 0.782 m

8 0

2 years ago

How many molecules are there in 8.25 moles of CaHia?

expeople1 [14]

The number of molecules : 4.967 x 10²⁴

<h3>Further explanation </h3>

A mole is a number of particles(atoms, molecules, ions) in a substance

This refers to the atomic total of the 12 gr C-12 which is equal to 6.02.10²³, so 1 mole = 6.02.10²³ particles

Can be formulated :

N = n x No

N = number of particles

n = mol

No = 6.02.10²³ = Avogadro's number

8.25 moles of C₈H₁₈

The number of molecules :

$\tt 8.25\times 6.02\times 10^{23}=4.967\times 10^{24}$

8 0

3 years ago