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Bezzdna [24]
3 years ago
9

PLEASE HELP

Chemistry
2 answers:
timama [110]3 years ago
7 0

Answer : The correct options are, H_2O\text{ and }CO

Explanation :

Covalent compound : It is defined as the compound which is formed by the sharing of electrons between the atoms forming a compound.

The covalent compound are usually formed when two non-metals react.

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

Ionic compound are usually formed when a metal reacts with a non-metal.

(1) Magnesium oxide (MgO) : In this compound, magnesium is a metal and oxygen is non-metal. When magnesium atom donates electron to oxygen atom then it forms an ionic compound.

(2) Water (H_2O) : In this compound, hydrogen and oxygen is non-metal. When hydrogen and oxygen atom share their electron then it forms a covalent compound.

(3) Sodium fluoride (NaF) : In this compound, sodium is a metal and fluorine is non-metal. When sodium atom donates electron to fluorine atom then it forms an ionic compound.

(4) Carbon monoxide (CO) : In this compound, carbon and oxygen is non-metal. When carbon and oxygen atom share their electron then it forms a covalent compound.

Hence, the correct options are, H_2O\text{ and }CO

muminat3 years ago
5 0

Answer:

H2O and CO

Explanation:

they both form covalent bonds because none both of the elements are non-metal. Mgo and NaF both have metals in them so they would form ionic bonds.

Covalent bonds, two non-metal

Ionic bonds, a metal and a non-metal

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Billy the friendly Robot uses 50 N of force to lift a box 2 meters in the air. How much work did Billy perform?
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Answer:

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Explanation:

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4 0
3 years ago
PLEASE HELP!!!!!!
pogonyaev

Answer:

m_{B}^{theoretical}=0.365gB

Y=87.1\%

Explanation:

Hello there!

In this case, since the reaction (A->B) have an initial amount of pure 4-aminobenzoic acid, the first step to compute the theoretical yield is to solve the following stoichiometric setup:

m_{B}^{theoretical}=0.303gA*\frac{1molA}{137.14gA}*\frac{1molB}{1molA}*\frac{165.19 gB}{1molB}\\\\   m_{B}^{theoretical}=0.365gB

Whereas A stands for 4-aminobenzoic acid and B for the benzocaine. Moreover, we compute the percent yield by dividing the actual yield (0.318 g) by the theoretical one (0.365 g):

Y=\frac{0.318g}{0.365g} *100\%\\\\Y=87.1\%

Best regards!

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