There are 3 main process in the water cycle; evaporation, condensation, and precipitation. What energy source starts the process
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Answer:
pH of the solution will slightly increase as it becomes less acidic for which it turns out to be more diluted.
Explanation:
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In this case, according to the given information, it turns out possible for us to calculate the pH change of the solution by firstly calculating the HCl concentration, as equal to that of the hydrogen ions whose pH is 2 as this is a strong acid:
Now, since water is added to the solution, but we do not have the initial volume of this solution, we can ensure that its pH will increase, become less acidic, because the concentration of the acid, and consequently that of the hydrogen ions, is diminished as the volume is increased.
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This hypothetical process would produce actinium-230.
<h3>Explanation</h3>An alpha decay reduces the atomic number of a nucleus by two and its mass number by four.
There are two types of beta decay: beta minus β⁻ and beta plus β⁺.
The mass number of a nucleus <em>stays the same</em> in either process. In β⁻ decay, the atomic number <em>increases </em>by one. An electron e⁻ is produced. In β⁺ decay, the atomic number <em>decreases </em>by one. A positron e⁺ is produced. Positrons are antiparticles of electrons.
β⁻ are more common than β⁺ in decays involving uranium. Assuming that the "beta decay" here refers to β⁻ decay.
Gamma decays do not influence the atomic or mass number of a nucleus.
Uranium has an atomic number of 92. 238 is the mass number of this particular isotope. The hypothetical product would have an atomic number of 92 - 2 ⨯ 2 + 1 = 89. Actinium has atomic number 89. As a result, the product is an isotope of actinium. The mass number of this hypothetical isotope would be 238 - 2 ⨯ 4 = 230. Therefore, actinium-230 is produced.
The overall nuclear reaction would involve five different particles. On the reactant side, there is
- one uranium-238 atom.
On the product side, there are
- one actinium-230 atom,
- two alpha particles (a.k.a. helium-4 nuclei),
- one electron, and
- one gamma particle (a.k.a. photon).
Consider: what would be the products if the nucleus undergoes a β⁺ decay instead?