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zaharov [31]
3 years ago
14

What is the order of operation of 100 + 6² - 9

Mathematics
1 answer:
Kipish [7]3 years ago
6 0
Okay so you would use PEMDAS (parentheses, exponents, multiply, divide, add, and subtract) so there are no parentheses so you do the exponents
{6}^{2}  =  36
then you do the rest so 100+36=136 and then 136-9=127 so the answer is 127
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Answer:

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A geometric progression has a third term of 20 and a sum of infinity which is 3 times the first term. Find the first term ​
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Step-by-step explanation:

Step 1: The formular for the nth term is ar^n-1 and since we're solving for the third term ar^3-1 = ar² which is equal to 20

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3a= a/(1-r)

We simplify Futher by multiplying both sides by (1-r)

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Make 3ar the subject of the formula

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Step 3: From the first equation since ar²=20, let's make a the subject of the formula by dividing both sides by r²

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A=20/r²lets make this equation (iii)

Step 4: subtitle a as 20/r² into equation (ii)

Since 3ar=2a

Then 3.(20/r²).r = 2. 20/r²

= (60/r²) .r = 40/r²

60/r = 40/r2

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= r = 2/3

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= 4a = 180

= a = 180/4

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