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2 years ago

I’ll give Brainly est help. B

Mathematics

1 answer:

natulia [17]2 years ago

5 0

Answer:

C) 99 + 3x

Step-by-step explanation:

Since it's always going to cost 99, it'll stay like that since it's a constant

Since it's 3 PER person, that means 3 will have a variable: 3x

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If f(x)=x^2 and g(x)=1÷2x+3 find g(f(-1))

gogolik [260]

ANSWER

$g(f( - 1)) = \frac{1}{5 }$

EXPLANATION

The given function is:

$f(x) = {x}^{2}$

and

$g(x) = \frac{1}{2x + 3}$

$g(f(x)) = g( {x}^{2} )$

$g(f(x)) = \frac{1}{2{x}^{2} + 3 }$

To find g(f(-1)), we substitute x=-1, to obtain;

$g(f( - 1)) = \frac{1}{2{( - 1)}^{2} + 3 }$

We simplify the square in the denominator to get,

$g(f( - 1)) = \frac{1}{2+ 3 }$

We now add the denominator to obtain;

$g(f( - 1)) = \frac{1}{5 }$

6 0

3 years ago

True or false? a tangent line is a line that intersects a circle at exactly one point. APEX

Sever21 [200]

Answer:

I believe its true

3 0

2 years ago

Read 2 more answers

A water park sold 14 child tickets and 6 adult tickets. What percentage of

steposvetlana [31]

Total tickets sold :
14 + 6 = 20

fraction of child tickets sold = 14/20

then, we convert this fraction to %.

14/20 = 70/100
( multiply by 5 )

percentage = 70%

5 0

2 years ago

Read 2 more answers

Wo runners are saving money to attend a marathon. The first runner has $112 in savings, received a $45 gift from a friend, and w

SpyIntel [72]

Answer:

I believe the last answer is correct

Step-by-step explanation:

Both runners are gaining money

8 0

2 years ago

Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are

Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

$P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}$ .

Recall that $\binom{n}{k}= \frac{n!}{k!(n-k)!}$ In this case, the student passes if X is at least four correct questions, then

$P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696$

c)The expected value of a binomial random variable with parameters n and p is $E[X] = np$ . IN our case, n=6 and p =0.2. Then the expected value of correct answers is $6\cdot 0.2 = 1.2$

5 0

3 years ago