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katovenus [111]
3 years ago
9

Which polynomial could have the following graph?

Mathematics
2 answers:
zubka84 [21]3 years ago
8 0
Hi,
Roots are 2, -1,-3.So y=(x-3)(x+1)(x+3)
Answer B
babunello [35]3 years ago
8 0

Answer: y=(x-2)(x+1)(x+3)

Step-by-step explanation:

From the given graph, it can be seen that the x intercepts of the graph are

x=-3,\ x=-1,\ x=2

It implies the value of y at the above points must be zero.

[x-intercept is of the form (a,0), where the value of y is zero.]

It implies x=-3,\ x=-1,\ x=2 are the zeroes of the polynomial graphed.

It implies (x-2),\ (x+1),\ (x+3) are the factors of the polynomial graphed.

[By Factor theorem]

Thus the polynomials should be :  y=(x-2)(x+1)(x+3) which is the correct polynomial for the given graph.

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Find the vertex: y=1/2 x^2+2x-3<br><br> Please explain how to find the answer too!
Kryger [21]

Answer:

(-2,-5)

Step-by-step explanation:

Y=x^2/2 +2x-3

Y=1/2 ×(x+2)^2 -5

a=1/2

h=-2

k=-5

(-2,-5)

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2 years ago
Four less than the product of 2 and a number is the same as negative eightteen. Find the number
dolphi86 [110]

Answer:

12

Step-by-step explanation:

4-2x=-18

-4        -4

-2x=-24

-2      -2

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3 years ago
What is mA?<br> Enter your answer in the box.
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Answer:

X=3.75

Step-by-step explanation:

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6 0
2 years ago
F(x)=2x^2-x-6 g(x)=4-x (f+g)(x)
Semenov [28]

\large  \boxed{(f + g)(x) = f(x) + g(x)}

The property above is distribution property where we distribute x-term in the function.

Substitute both f(x) and g(x) in.

\large{ \begin{cases} f(x) = 2 {x}^{2}   -  x - 6 \\ g(x) =  4 - x \end{cases}}  \\  \large{f(x) + g(x) = (2 {x}^{2}  - x - 6) + (4 - x)} \\  \large{f(x) + g(x) = 2 {x}^{2}  - x - 6 + 4 - x}

Évaluate/Combine like terms.

\large{f(x)  + g(x) = 2 {x}^{2}  - 2x - 2}

The function can be factored so there are two answers. (Both of them work as one of them is factored form while the other one is not.)

\large{(f + g)(x) = 2 {x}^{2}  -2x -2}

<u>Alternative</u>

\large{(f + g)(x) = 2({x}^{2}  -x - 1)}

<u>Answer</u>

  • (f+g)(x) = 2x²-2x-2
  • (f+g)(x) = 2(x²-x-1)

Both answers work. The second answer is in factored form.

Let me know if you have any doubts!

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