All categories

3 years ago

You burn 270 grams of glucose during respiration. How

Chemistry

1 answer:

BlackZzzverrR [31]3 years ago

8 0

Answer:

396 g OF CO2 WILL BE PRODUCED BY 270 g OF GLUCOSE IN A RESPIRATION PROCESS.

Explanation:

To calculate the gram of CO2 produced by burning 270 g of gucose, we first write out the equation for the reaction and equate the two variables involved in the question;

C6H12O6 + 6O2 -------> 6CO2 + 6H2O

1 mole of C6H12O6 reacts to form 6 moles of CO2

Then, calculate the molar mass of the two variables;

Molar mass of glucose = ( 12 *6 + 1* 12 + 16* 6) g/mol = 180 g/mol

Molar mass of CO2 = (12 + 16 *2) g/mol = 44 g/mol

Next is to calculate the mass of glucose and CO2 involved in the reaction by multiplying the molar mass by the number of moles

1* 180 g of glucose yields 6 * 44 g of CO2

180 g of glucose = 264 g of CO2

If 270 g of glucose were to be used, how many grams of CO2 will be produced;

so therefore,

180 g of glucose = 264 g of CO2

270 g of glucose = x grams of CO2

x = 264 * 270 / 180

x = 71 280 / 180

x = 396 g of CO2.

In other words, 396 g of CO2 will be produced by respiration from 270 g of glucose.

You might be interested in

What are the coefficients?

jenyasd209 [6]

The numbers in front of the formulas

5 0

3 years ago

Write the balanced equation for the reaction of aqueous sodium carbonate and aqueous calcium chloride dihydrate to form solid ca

faltersainse [42]

Na2CO3 (aq) + CaCl2H4O2 (aq) = CaCO3 (s) + 2 NaCl (aq) + 2 H2O (l)

5 0

3 years ago

Read 2 more answers

You have a red ballooe that has a volume of 20 liters, a pressure of 1.5 atmospheres and a temperature of 28 C. What is the volu

ki77a [65]

Explanation:

The given data is as follows.

$P_{1}$ = 1.5 atm, $V_{1}$ = 20 L, $T_{1}$ = (28 + 273) K = 301 K

$P_{2}$ = 5 atm, $V_{2}$ = ?, $T_{2}$ = (50 + 273) K = 323 K

Formula to calculate the volume will be as follows.

$\frac{P_{1} \times V_{1}}{T_{1}}$ = $\frac{P_{2} \times V_{2}}{T_{2}}$

Putting the given values into the above formula as follows.

$\frac{P_{1} \times V_{1}}{T_{1}}$ = $\frac{P_{2} \times V_{2}}{T_{2}}$

$\frac{1.5 atm \times 20 L}{301 K}$ = $\frac{5 atm \times V_{2}}{323 K}$

$V_{2}$ = 0.64 L

Thus, we can conclude that the change in volume of the balloon will be 0.64 L.

6 0

3 years ago

Why is true about electron dot diagrams

vazorg [7]

Answer: The correct answer is the option: B. An element with eight valence electrons is chemically unstable.

Explanation:

Hello! Let's solve this!

We will analyze each of the options:

A. The group number of the element provides a clue to the number of valence electrons: it is correct, since it provides the number of valence electrons.

B. An element with eight valence electrons is chemically unstable: this is not correct, since elements with eight electrons in the valence shell cannot react because they already have the last complete shell. Therefore, they are chemically stable.

C. The points must be placed one at a time on each side of the chemical symbol: it is correct, because that is the way to make the point diagram.

D. An atom is chemically stable if all the points are paired: this is correct since this verifies that the point diagram has been done well.

We conclude that the correct answer is the option: B. An element with eight valence electrons is chemically unstable.

Hope this helps..... Stay safe and have a Merry Christmas!!!!!!!!! :D

7 0

3 years ago

A flask with a volume of 3.16 l contains 9.33 grams of an unknown gas at 32.0°c and 1.00 atm. What is the molar mass of the gas?

Inessa05 [86]

Answer:

73.88 g/mol

Explanation:

For this question we have to keep in mind that the unknown substance is a gas, therefore we can use the ideal gas law: