The Answer is A
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Answer:
0.0991 M
Explanation:
Step 1: Write the neutralization reaction between oxalic acid and sodium hydroxide.
H₂C₂O₄ + 2 NaOH = Na₂C₂O₄ + 2 H₂O
Step 2: Calculate the moles of oxalic acid
The molar mass of H₂C₂O₄ is 90.03 g/mol. The moles corresponding to 153 mg (0.153 g) are:

Step 3: Calculate the moles of sodium hydroxide
The molar ratio of H₂C₂O₄ to NaOH is 1:2.

Step 4: Calculate the molarity of sodium hydroxide

Answer:
Ksp = 2.74 x 10⁻⁵
Explanation:
The solubility equilibrium for Ca(OH)₂ is the following:
Ca(OH)₂(s) ⇄ Ca²⁺(aq) + 2 OH⁻(aq)
I 0 0
C + s + 2s
E s 2s
According to the ICE table, the expression for the solubility product constant (Kps) is:
Ksp = [Ca²⁺] x ([OH⁻])² = s x (2s)² = 4s³
Then, we calculate Ksp from the solubility value (s):
s = 0.019 M
⇒ Ksp = 4s³ = 4 x (0.019)³ = 2.74 x 10⁻⁵
Answer:
Molar Mass of CH2O2 is 46.026
Explanation:
What is the molar mass of CH2O2 ? ( C= 12.01 g/mol, H=1.008 g/mol, O=16.00)
C = 12.01g/mol
H = 1.008g/mol
O = 16g/mol
CH2O2 = 12.01+1.008x2+16x2 = 46.026g/mole