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Leona [35]
3 years ago
6

A 42.0 mL sample of an NaOH solution is placed in a flask with a few drops of phenolphthalein (indicator). If 11.7 mL of a 0.325

M HCl solution is needed to reach the endpoint, what is the molarity of the NaOH solution?
NaOH(aq) + HCl(aq) H2O(l) + NaCl(aq)
Chemistry
1 answer:
olganol [36]3 years ago
8 0
Please like if you get the answer :)

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Pls answer
Kitty [74]

Answer:

Kinetic energy to Electrical energy.

Explanation:

When stationary bike is pedaled the wheels of the bike rotates which is a form of kinetic energy, this kinetic energy can be converted into electricity when connected to a generator.

From _Kinetic_ energy to _Electrical_ energy.

7 0
3 years ago
In a science experiment, Javi concludes that a chemical reaction has occurred. What evidence would support this conclusion?
Naily [24]

Answer:

B) a substance's color and odor changed        Explanation: A signal that a chemical change has occurred is when its odor (its smell) or its appearance has changed.

8 0
3 years ago
Read 2 more answers
An exothermic reaction is a chemical reaction that produces _____.
lana66690 [7]
I pretty sure the answer is a
8 0
3 years ago
Which of the following pH numbers indicates a strong alkali?<br> a. 1<br> b. 5<br> c. 7<br> d.) 14
pochemuha

Answer:

1 is the correct answer of the question

7 0
3 years ago
Given the reaction: 2na + 2h2o → 2na+ + 2oh− + h2
Neporo4naja [7]

Answer:

\large \boxed{\text{3. Na}}

Explanation:

We can use oxidation numbers to decide which substance is reduced.  

\rm 2\stackrel{\hbox{0}}{\hbox{Na}} + 2\stackrel{\hbox{+1}}{\hbox{ H}_{2}}\stackrel{\hbox{-2}}{\hbox{O}}\longrightarrow \rm 2\stackrel{\hbox{+1}}{\hbox{Na}^{+}} + 2\stackrel{\hbox{-2}}{\hbox{O}}\stackrel{\hbox{+1}}{\hbox{H}^{-}} + \stackrel{\hbox{0}}{\hbox{H}_{2}}

The oxidation number of Na changes from 0 in Na to +1 in Na⁺.

The oxidation number of H changes from +1 in H₂O to 0 in H₂.

\text{An increase in oxidation number is oxidation, so $\large \boxed{\textbf{Na}}$ is the substance oxidized.}

1 and 4 are wrong because H₂ and Na⁺ are products.

2. is wrong because there is no H⁺ to be oxidized or reduced.

3 0
3 years ago
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