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maria [59]
4 years ago
10

A container with a fixed volume, filled with hydrogen gas at -104°C and 71.8 K PA is heated until the pressure reaches 225.9 K P

A. What is the temperature of the hydrogen gas in degrees Celsius
Chemistry
1 answer:
Daniel [21]4 years ago
4 0

Answer:

The correct answer is 532 K

Explanation:

The Gay-Lussac law describes the behavior of a gas at constant volume, by changing the pressure or temperature. When is heated, the change in pressure of the gas is directly proportional to it absolute temperature (in Kelvin or K).

We have the following initial conditions:

P1= 71.8 kPa

T1= -104ºC +273 = 169 K

If the pressure increases until reaching 225.9 kPa (P2), we can calculate the final temperature of the gas (T2) by using the Gay-Lussac derived expression:

P1 x T2 = P2 x T1

⇒T2= (P2 x T1)/P1 = (225.9 kPa x 169 K)/71.8 kPa= 531.7 K ≅ 532 K

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A common laboratory method for preparing a precipitate is to mix solutions containing the component ions. Does a precipitate for
laiz [17]

Answer:

CaF2 will not precipitate

Explanation:

Given

Volume of Ca(NO3)2 = 10 ml

Molar concentration of Ca(NO3)2 = 0.001

Volume of NaF = 10 ml

Molar concentration of  NaF  = 0.0001

Ksp for CaF2 = 3.2 * 10^ {-11}

CaF2 will precipitate if Q for the reaction is greater than ksp of CAF2

Moles of calcium ion

= 10 * 0.001\\= 0.01

[Ca2+] = \frac{0.01}{10 + 10} \\= \frac{0.01}{20} \\= 5 * 10^{-4}

Moles of F- ion

= 10 * 0.0001\\= 0.001

[F-] = \frac{0.001}{10 + 10} \\= \frac{0.001}{20} \\= 5 * 10^{-5}

Q = [Ca2+] [F-]^2\\= (5 * 10^{-4}) * (0.5* 10^-4)\\= 1.25 * 10^{-12}

Q is lesser than Ksp value of CaF2. Hence it will not precipitate

5 0
3 years ago
2.An atom with 35 mass number has 17
shusha [124]

Answer:

mass no = A

Atomic number = Z= no of protons

Neutron = n

n = A-Z

n= 35- 17

   = 18

Explanation:

7 0
3 years ago
If 3.5 g H2 react with 18.7 g O2 what is the limiting reactant?
Pachacha [2.7K]
O2 is the limiting reactant 

3 0
4 years ago
Read 2 more answers
Calculate the change in the standard entropy of the system, delta s degree for the synthesis of ammonia from N_2(g) and H_2(g) a
Svet_ta [14]

Answer:

\Delta S^{0} for the reaction is -198.762 J/K

Explanation:

N_{2}(g)+3H_{2}(g)\rightarrow 2NH_{3}(g)

Standard change in entropy for the system (\Delta S^{0}) is given by-

\Delta S^{0}=[2moles\times S^{0}(NH_{3})_{g}]-[1mole\times S^{0}(N_{2})_{g}]-[3\times S^{0}(H_{2})_{g}]

where S^{0} represents standard entropy.

Here S^{0}(NH_{3})_{g}=192.45J/(K.mol), S^{0}(N_{2})_{g}=191.61J/(K.mol) and S^{0}(H_{2})_{g}=130.684J/(K.mol)

So, \Delta S^{0}=[2\times 192.45]-[1\times 191.61]-[3\times 130.684]J/K=-198.762J/K

3 0
3 years ago
You should be able to see small bubbles forming where the bromine solution falls into the flask. if the humidity is high enough
allochka39001 [22]

If the humidity is high enough we may notice fumes rising out of the mixture containing Br solution. The fumes produced are HBr fumes.

<h3>What is hydrogen bromide? </h3>

Hydrogen bromide (HBr) is a corrosive and toxic gas. It can be fatal if it is inhaled. It is very corrosive to our respiratory system, to our eyes, and when it is in contact with skin. When it is in mist form or in a liquid form it will cause burns to all tissue if it falls upon.

<h3>Why fumes are produced? </h3>

Hydrogen Bromide is a highly irritating, corrosive, nonflammable gas having a pungent odor at room temperature. It will fume in air which have high humidity because formation of hydrobromic acid takes place; it is the diatomic molecule.

Under ordinary conditions hydrogen bromide is a gas but it can be converted into liquid. Hydrobromic acid is then formed after hydrogen bromide is dissolved in water.

Thus we concluded that the fumes produced when bromine solution is in contact with moist air is HBr fumes.

learn more about HBr:

brainly.com/question/2712747

#SPJ4

6 0
1 year ago
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