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OverLord2011 [107]
3 years ago
12

Calculate the empirical formula for DCBN, given that the percent composition is 48.9%C, 1.76%H, 41.2%Cl, and 8.15%N.

Chemistry
1 answer:
sweet [91]3 years ago
5 0

Answer:

empirical formula is C7H3NCl2

Explanation:

too much work too explain and im lazy

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How many moles of nitrogen are in 2.0×10−2mole of quinine?
galben [10]

Answer: 4 x 10 ∧-2  moles of nitrogen.

Explanation:

The chemical formular for quinine is ; C20 H24 N2 O2

As can be seen from the chemical formular;

1 mole of quinine contains 2 moles of Nitrogen

Thus; 2.0 x 10 ∧-2 moles of quinine would contain

         2.0 x 10 ∧-2 x 2 = 4 x 10 ∧-2  moles of nitrogen.

 Therefore 4 x 10 ∧-2  moles of nitrogen are in 2.0×10−2mole of quinine        

7 0
3 years ago
Chemical Reactions
irakobra [83]

Answer:

It works by separating the fuel from the oxygen. The oxygen comes from the air. It is the same oxygen we breathe. Since the oxygen has to be in contact with the fuel, if you can coat the fuel with something that keeps the oxygen away, the fire will go out which is what the fire extinguisher does.

6 0
2 years ago
An Equilibrium with Cobalt Complex Ions.Investigate the equilibrium between two different complex ions of cobalt. The reaction i
Paladinen [302]
  • The change in color from blue to pink of the cobalt complexes here has been the basis of cobalt chloride indicator papers for the detection of the presence of water. It is also used in self-indicating silica gel desiccant granules.
  • Pink cobalt species + chloride ions ⇌ Blue cobalt species + water molecules

<u>Explanation</u>:

  • The adjustment in color from blue to the pink of the cobalt complexes here has been the premise of cobalt chloride indicator papers for the detection of the presence of water. It is likewise utilized in self-demonstrating silica gel desiccant granules.  

Pink cobalt species + chloride particles ⇌ Blue cobalt species + water molecules  

  • The response of [Co(H2O)6]2+(aq) + 4Cl–(aq) → [CoCl4]2–(aq) + 6H2O(l) is endothermic. In this manner, as per Le Chatelier's rule, when the temperature is raised, the situation of the balance will move to one side, shaping a greater amount of the blue complex particle at the expense of the pink species.  
  • Including concentrated hydrochloric raises the chloride particle fixation, making the equilibrium move to one side, as per Le Chatelier. Including water brings down the chloride particle fixation, moving the equilibrium the other way.
  • As an extension, it is conceivable to show that it is the Cl–particles in the hydrochloric acid that move the balance by including a spatula of sodium chloride rather than the pink arrangement. This delivers a bluer color, however, this may take some time because the salt is delayed to dissolve.
5 0
3 years ago
Your experiment requires 150 mL of 7.7 M NaOH. How many grams of NaOH will you need?
Elodia [21]
You have molarity and you have volume. Use the formula :
Molarity(M)= Moles(N)/Liter(L)            to get the solution. 
150 ml= .150 L
7.7 = N/.150
N=.1.155 moles of NaOH.
 And since you know the moles, use the molar mass to figure out the grams.
<span> (40g/mol NaOH) x (1.155mol) =  
46.2 g of NaOH.</span>
7 0
3 years ago
The final charge on each of the three separated spheres in part (b) is +3.0 μC. How many electrons would have to be added to one
marishachu [46]

Answer:

1.873\times 10^{13} electrons should be added to one of these spheres to make it electrically neutral.

Explanation:

Total charge on each sphere =  +3.0 μC =3\times 10^{-6} C

1 \mu C=10^{-6} C

In order to neutralize the positive charge equal magnitude of negative charge is to be added.

Total charge electrons, Q=  -3.0 μC =-3\times 10^{-6} C

Number of electrons = n

Charge on a single electron, e = -1.602\times 10^{-19} C

Q = n × e

-3\times 10^{-6} C=n\times (-1.602\times 10^{-19} C)

n=\frac{-3\times 10^{-6} C}{-1.602\times 10^{-19} C}=1.873\times 10^{13}

1.873\times 10^{13} electrons should be added to one of these spheres to make it electrically neutral.

4 0
3 years ago
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