Full Question
<em>Of the cartons produced by a company, 10% have a puncture, 6% have a smashed corner, and 0.4% have both a puncture and a smashed corner. Find the probability that a randomly selected carton has a puncture or a smashed corner. The probability that a randomly selected carton has a puncture or a smashed corner nothing ____%. (Type an integer or a decimal. Do not round.)</em>
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Answer:

Step-by-step explanation:
Given



Required

For non-mutually exclusive event described above, P(Punctured or Smashed Corner) can be calculated as thus;

Substitute:
10% for P(Puncture Corner),
6% for P(Smashed Corner) and
0.4% for P(Punctured and Smashed Corner)


Convert % to fraction

Convert to decimal


Step-by-step explanation:
Given: r = 4 cm
The surface area A of a sphere is given by


Answer:
200 miles
Step-by-step explanation:
1 cm = 50 miles
4 x 1 = 4 x 50 = 200
Answer:
A number line with an open circle on −2, a closed circle on 5, and shading in between
Step-by-step explanation:
solve it you get x>-2
and 3x <=15
x<=5
so its close on 5 and open on -2
8,000+100+30+6
first you do 6*1356 which is 8136 then just write the numbers as the place value