City hall to post office = 6 1/2 miles = represented by f
city hall to library site = 1 1/4 miles = represented by d
library site to post office = unknown. = represented by e
City hall to library site PLUS library site to post office IS EQUAL to city hall to post office
d + e = f
1 1/4 + e = 6 1/2
find e.
e = 6 1/2 - 1 1/4
e = 13/2 - 5/4
e = (13*2)/(2*2) - 5/4
e= 26/4 - 5/4
e = (26-5)/4
e = 21/4
e = 5 1/4 distance from library site to post office.
To check:
d + e = f
1 1/4 + e = 6 1/2
1 1/4 + 5 1/4 = 6 1/2
6 2/4 = 6 1/2
6 1/2 = 6 1/2
Answer:
QH = 227.8 km ≅ 228 km
Step-by-step explanation:
∵ The bearing from H to P is 084°
∵ The bearing from P to Q is 210°
∵ The distance from H to P = 340 km
∵ The distance from P to Q = 160 km
∴ The angle between 340 and 160 = 360 - 210 - (180 - 84) = 54°
( 180 - 84) ⇒ interior supplementary
By using cos Rule:
(QH)² = (PH)² + (PQ)² - 2(PH)(PQ)cos∠HPQ
(QH)² = 340² + 160² - 2(340)(160)cos(54) = 51904.965
∴ QH = 227.8 km ≅ 228 km
Answer:
A
Step-by-step explanation:
these two triangles are similar
therefore corresping sides are proportionate
12/8=9/x
12x=72
x=72/12=6
