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Inga [223]
3 years ago
15

If GJ = 7 and HJ = 6, then H ___ G.

Mathematics
2 answers:
bagirrra123 [75]3 years ago
8 0

Answer: Option (a) is the correct answer.

Step-by-step explanation:

The given equation is as follows.

             GJ = 7 and HJ = 6

Solving for J as follows.

          J = \frac{7}{G} .......... (1)

and,    J =  \frac{6}{H} .......... (2)  

Now, equating the values of Both equation (1) and (2) as follows.

       \frac{7}{G} = \frac{6}{H}

              7H = 6G

or,           H = \frac{6G}{7}

                  = 0.85G

This means that the value of G is 0.85 times greater than H.

Thus, we can conclude that H < G.

           


MrMuchimi3 years ago
5 0
When H<G because if H is 6 and G is 7 , G is bigger than H
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Can you help with these two questions?
Lady bird [3.3K]

1) 155.91 grams would be left after 10 years

2) The population would be 376,478 in 2040

Step-by-step explanation:

The form of the exponential function is y=a(b)^{x} , where

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  • b is the growth/decay factor
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  • b = 1 - r, where r is the rate of decay

1)

Scientists are studying a 500 grams sample of a radioactive element, which has an annual decay rate of 11%

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∴ a = 500

∵ The annual decay rate is 11%

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∵ b = 1 - r ⇒ decay

∴ b = 1 - 0.11 = 0.89

- We need to find how many grams of the sample would be left

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∵ y=500(0.89)^{10}

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155.91 grams would be left after 10 years

2)

In 2000, the population of an Ohio town was 140,212. The population is expected to grow at a rate of 2.5% each year

∵ The population of an Ohio town was 140,212

∴ a = 140.212

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Learn more:

You can learn more about the functions in brainly.com/question/11921476

#LearnwithBrainly

6 0
3 years ago
Please Help!!
algol13
When you see questions of this nature, test the individual inequalities and look out for their intersection.

For
y < \frac{2}{3} x
Choose a point in the lower or upper half plane created by the line
y = \frac{2}{3} x
The above line is the one which goes through the origin.

Now testing (1,0) yields,

0 < \frac{2}{3} (1)
That is,

0 < \frac{2}{3}
This statement is true. So we shade the lower half of
y = \frac{2}{3} x

For
y \geqslant - x + 2
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The intersection is the region shaded in B. The top right graph
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