Question

A rover mission to another planet attempts to measure the value of g using a simple pendulum. Using a pendulum of length 55.0 cm , the rover measures 95.0 complete swings in a time of 125 s . Part A What is the value of g on this planet

Answer 1

Answer:

12.54 m/s²

Explanation:

T = Time period of pendulum = 125/95 s = 25/19 s

l = Length of pendulum = 55 cm

g = Acceleration due to gravity

Time period of pendulum is given by

$T=2\pi \sqrt{\frac{l}{g}}\\\Rightarrow g=4\pi^2\frac{l}{T^2}\\\Rightarrow g=4\pi^2\frac{0.55}{\frac{25}{19}^2}=12.54\ m/s^2$

∴ The g on this planet is 12.54 m/s²