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nataly862011 [7]
3 years ago
5

Suppose two comets, comet A and comet B, were orbiting the Sun, having the same average orbital radii. If comet A had a higher e

ccentricity than comet B, which comet would, during some portion of its orbit, have the highest orbital speed?
Physics
1 answer:
arsen [322]3 years ago
5 0

Answer:

Explanation:

It is given that comet A has higher eccentricity than comet B and according to Kepler law planet orbit around the sun with the sun as the focus.

An implication of Kepler's law is that the planet moves faster when it close to the sun and slower when distant. This is the result of the conservation of angular momentum.

A has a more elliptical path thus it will be closer to the sun and therefore A will have the highest orbital speed.

You might be interested in
What conversion factor is used to convert 20 cm to m
Anastaziya [24]
The conversion factor you use is 100 cm = 1 m.
You can divide 20 by 100 to get the answer.
20 cm/100 cm =.2 m
Hope this helped!
7 0
3 years ago
Help me pls its for my science class i need to show my work
Lostsunrise [7]

Answer:

P = 5880  J

Explanation:

Given that,

The mass of the block, m = 30 kg

The block is sitting at a height of 20 m.

The block will have gravitational potential energy. The formula for gravitational potential energy is given by :

P=mgh\\\\=30\times 9.8\times 20\\\\=5880\ J

So, the required potential energy is equal to 5880  J.

6 0
2 years ago
6. Протон с кинетична енергия Ek = 1,6.10 J, който се
anzhelika [568]

Answer:

Tahukah kamu, mengapa motor berhenti di depan lampu merah?

karena motornya direm. Coba kalau nggak direm bisa bahaya tuh.

Tebak binatang apa yang jago renang?

Bebek. Kalau ikan bukan renang tapi menyelam

Kenapa di rel kereta api ditaruh batu?

Soalnya kalau ditaruh duit nanti pada diambil.

3 0
3 years ago
which pole of a compass needle points north ? please give simple answer with little explaining if any :)
Mumz [18]
I think the North Pole
If I understand this correctly
6 0
3 years ago
A car moving with an intial velocity of 60m/s is brought to rest in 30 seconds calculate the acceleration
gregori [183]

Answer:

a = 2 [m/s^2]

Explanation:

To solve this problem we must use the expressions of kinematics, we must bear in mind that when a body is at rest its velocity is zero.

v_{f} = v_{i} - (a*t)

where:

Vf = final velocity = 0

Vi = initial velocity = 60 [m/s]

a = desacceleration [m/s^2]

t = time = 30 [s]

Note: the negative sign of the above equation means that the car is slowing down, i.e. its speed decreases.

0 = 60 - (a*30)

a = 2 [m/s^2]

6 0
3 years ago
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