When a mixture of 10 moles of SO2 and 15 moles of O2 was passed over a catalyst, 10 moles of SO3 was formed.
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Answer:
GAY-LUSSAC'S LAW.
Explanation:
P1 = 765 torr
T1 = 23°C = 296K
P2 = 560. torr
T2 = ?
(765 torr)/(296K) = (560. torr)/ T2
T2 = 226 K = -57°C