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Tom [10]
4 years ago
14

When the temperature of a sample of pure water is raised above 25 °C,(1)the hydronium ion concentration will be greater than the

hydroxide ion concentration.(2)the hydronium ion concentration will be less than the hydroxide ion concentration.(3)the value of Kw will increase.(4)the hydronium ion concentration could change to 1.0 × 10−10 M.(5)the hydroxide ion concentration could change to 1.0 × 10−10 M.
Chemistry
1 answer:
Ludmilka [50]4 years ago
5 0

Answer:

The correct answer is option 3.

Explanation:

H_2O\rightleftharpoons H^++OH^-

The expression of K_w is given by :

K_w=[H^+][OH^-]

K_w\propto [H^+]

K_w\propto [OH^-]

Rise in temperature will result in more dissociation of water molecules into hydrogen ions and hydroxide ions.

With an increase in concentration of hydrogen ions and hydroxide ions value of K_w will also increase.

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Answer:

See to them if they are balanced, i.e., the no. of atoms of each element should be equal on both the sides. If they are so, then its adhered to law of conservation of matter.

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3 years ago
Q11 : why b is correct
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B is correct because it doesn't depend on the movement just how the partials move at boiling point, ie it will expand but not gain motion
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2 years ago
On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 25
Taya2010 [7]

The new volume of the bag : 747.43 ml

<h3>Further explanation</h3>

Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

V₁=250 ml

T₁=19+273=292 K

T₂=600+273=873 K

\tt V_2=\dfrac{V_1.T_2}{T_1}\\\\V_2=\dfrac{250\times 873}{292}\\\\V_2=747.43~ml

7 0
3 years ago
How many molecules of F2 react with 66.6 g NH3 ? (stoichiometry)
stiks02 [169]
<h3>Answer:</h3>

5.89 × 10^23 molecules of F₂

<h3>Explanation:</h3>

The equation for the reaction between fluorine (F₂) and ammonia (NH₃) is given by;

5F₂ + 2NH₃ → N₂F₄ + 6 HF

We are given 66.6 g NH₃

We are required to determine the number of fluorine molecules

<h3>Step 1: Moles of Ammonia </h3>

Moles = Mass ÷ Molar mass

Molar mass of ammonia = 17.031 g/mol

Moles of NH₃ = 66.6 g ÷ 17.031 g/mol

                      = 3.911 moles

<h3>Step 2: Moles of Fluorine </h3>

From the equation 5 moles of Fluorine reacts with 2 moles of ammonia

Therefore,

Moles of fluorine = Moles of Ammonia × 5/2

                            = 3.911 moles × 5/2

                           = 9.778 moles

<h3>Step 3: Number of molecules of fluorine </h3>

We know that 1 mole of a compound contains number of molecules equivalent to the Avogadro's number, 6.022 × 10^23 molecules

Therefore;

1 mole of F₂ = 6.022 × 10^23 molecules

Thus,

9.778 moles of F₂ = 9.778 moles × 6.022 × 10^23 molecules/mole

                              = 5.89 × 10^23 molecules

Therefore, the number of fluorine molecules needed is 5.89 × 10^23 molecules

5 0
3 years ago
Use the drop-down menus to match the name and structure for the following cycloalkanes. A five-sided polygon. A square. A five-s
Mashutka [201]

Answer:

A five-sided polygon.- cyclopentane

A square.- cyclobutane

A five-sided polygon with one line extending from a point.- methylcyclopentane

A 6-sided polygon with a line extending from one point to a C H 3.- methlcyclohexane

Explanation:

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