Given :
pH of solution of mixture of lactic acid and lactate is 4.26 .
To Find : ![log( \dfrac{[ \text{Conc. of lactate}]}{[\text{Conc . of lactic acid }]}) = 0.4](https://tex.z-dn.net/?f=log%28%20%5Cdfrac%7B%5B%20%5Ctext%7BConc.%20of%20lactate%7D%5D%7D%7B%5B%5Ctext%7BConc%20.%20of%20lactic%20acid%20%7D%5D%7D%29%20%20%3D%200.4)
The ratio of the lactate concentration to the lactate .
Solution :
We know , pKa of lactic acid is :
pKa = 3.86 .
Now , the solution of lactic acid and lactate is a buffer solution .
So , pHof buffer acid is given by :
![pH=pKa+log(\dfrac{[Salt]}{[Acid]})](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%5Cdfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D%29)
Putting all given values :
![log( \dfrac{[ \text{Conc. of lactate}]}{[\text{Conc . of lactic acid }]}) = 0.4](https://tex.z-dn.net/?f=log%28%20%5Cdfrac%7B%5B%20%5Ctext%7BConc.%20of%20lactate%7D%5D%7D%7B%5B%5Ctext%7BConc%20.%20of%20lactic%20acid%20%7D%5D%7D%29%20%20%3D%200.4)
Taking anti log both the sides , we get :
![\dfrac{[ \text{Conc. of lactate}]}{[\text{Conc . of lactic acid }]} = 2.51](https://tex.z-dn.net/?f=%5Cdfrac%7B%5B%20%5Ctext%7BConc.%20of%20lactate%7D%5D%7D%7B%5B%5Ctext%7BConc%20.%20of%20lactic%20acid%20%7D%5D%7D%20%20%3D%202.51)
Therefore , the ratio of the lactate concentration to the lactate is 2.51 .
Hence , this is the required solution .