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guajiro [1.7K]
3 years ago
5

A solution containing a mixture of lactic acid and lactate was found to have a pH of 4.26. Calculate the ratio of the lactate co

ncentration to the lac
Chemistry
1 answer:
Aleks04 [339]3 years ago
4 0

Given :

pH of solution of mixture of lactic acid and lactate is 4.26 .

To Find : log( \dfrac{[ \text{Conc. of lactate}]}{[\text{Conc . of lactic acid }]})  = 0.4

The ratio of the lactate concentration to the lactate .

Solution :

We know , pKa of lactic acid is :

pKa = 3.86 .

Now , the solution of lactic acid and lactate is a buffer solution .

So , pHof buffer acid is given by :

pH=pKa+log(\dfrac{[Salt]}{[Acid]})

Putting all given values :

log( \dfrac{[ \text{Conc. of lactate}]}{[\text{Conc . of lactic acid }]})  = 0.4

Taking anti log both the sides , we get :

\dfrac{[ \text{Conc. of lactate}]}{[\text{Conc . of lactic acid }]}  = 2.51

Therefore , the ratio of the lactate concentration to the lactate is 2.51 .

Hence , this is the required solution .

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Answer:

V₂ = 0.4 L

Explanation:

<u>Data:</u>

  • P₁ (initial pressure) = 500 torr
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<u>Wanted:</u>

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<u>Equation:</u>

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<u>Solution:</u>

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Answer:CALINE4 Model and Geographical Information System were used for

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Norma-Jean [14]

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A vial containing radioactive selenium-75 has an activity of 3.0 mCi/mL. If 2.6 mCi are required for a leukemia test, how many m
oksian1 [2.3K]

Answer : The 866.66\mu L must be administered.

Solution :

As we are given that a vial containing radioactive selenium-75 has an activity of 3.0mCi/mL.

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