1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
makvit [3.9K]
3 years ago
8

Identify the number with the correct number of significant figures for each step of the calculation and for the final answer. No

te that 2 is an exact number. y equals 2.10 StartBracket 9.0 plus 2 times 35.35 EndBracket. 2 (35.35) =
Chemistry
2 answers:
pav-90 [236]3 years ago
8 0

Answer:

70.70

Explanation:

Just got it right on edge

lara [203]3 years ago
7 0

Answer: The answer is 167

Explanation: This is because that was right on edg. so yea heart this tho plsss

You might be interested in
Need help, please. :)
wolverine [178]

A change of one unit on the pH scale represents a change in the concentration of hydrogen ions by a factor of 10, a change in two units represents a change in the concentration of hydrogen ions by a factor of 100. Thus, small changes in pH represent large changes in the concentrations of hydrogen ions.

6 0
2 years ago
A watt of is a unit of power equivalent to 1 joule per second (1 J/sec). In other words, a 60 watt light bulb consumes 60 joules
Juli2301 [7.4K]

The time the chocolate bar could power the laptop in hours is 0.00233 hrs.

Since 200 Calories of chocolate bar were burned to power the 100 Watt laptop, we need to find the number of joules on energy in 200 calories of chocolate bar.

Knowing that 4.2 Joules = 1 Calorie, then

200 Calories = 200 × 1 calorie = 200 × 4.2 Joules = 840 Joules

Since the power required by the laptop is 100 W = 100 J/s and Power, P = energy/time

so, time = energy/power

So, the time for the laptop to use 840 J of energy from the chocolate bar at a rate or power of 100 W = 100 J/s is

time = 840 J ÷ 100 J/s = 8.4 s

So, the time in hours is 8.4 s ÷ 3600 s/1 h = 0.00233 hrs (since 1 hr = 3600 s)

So, the time the chocolate bar could power the laptop in hours is 0.00233 hrs.

Learn more about time to power here:

brainly.com/question/17732603

7 0
2 years ago
How much energy is required to change the temperature of 50g of water from 20 C to 55 C?
bagirrra123 [75]
You beef go have this much energy 60g
6 0
3 years ago
Why is accurate body measurement important in dressmaking​
Lilit [14]

Answer:

Without taking body measurements, the fabric material can run out of supply if the tailor uses it too much. And more material is required to fix small dresses or suits. So when body measurements are taken accurately, the tailor will know the exact amount of material to be used.

Explanation:

3 0
2 years ago
What best describes what models are used for?
monitta

Explanation:

is b or c but i think asnwer is b

3 0
2 years ago
Other questions:
  • What percentage of radioactive substance remains after two half-lives
    6·1 answer
  • Is cutting your hair a physical or chemical change
    12·2 answers
  • What is asubstance that flows Called
    9·2 answers
  • Explain why, when the imidazole ring of histidine is protonated, the double-bonded nitrogen is the nitrogen that accepts the pro
    5·1 answer
  • Name the noble gas, which is isoelectronic to a strontium ion.
    10·1 answer
  • Is the equation above balanced or unbalanced? Explain? Worth 55 points.
    5·2 answers
  • (more then one answer) As a form of energy, light has specific properties such as color and brightness. Some properties can only
    8·2 answers
  • Draw the lewis structure for the polyatomic trisulfide s−23 anion. be sure to include all resonance structures that satisfy the
    9·1 answer
  • describe the relationship between the age of the rocks and their distance from the mid ocean ridge, please look at the picture t
    11·1 answer
  • How many molecules are present in 5.45 moles of NO? Use the space below to show your work.
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!